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ratelena [41]
3 years ago
13

In sodium chloride, which atom loses an electron?

Chemistry
2 answers:
s344n2d4d5 [400]3 years ago
5 0
B. sodium
explanation:
sodium is in front (NaCl), and the first element always loses an electron
Fittoniya [83]3 years ago
3 0

Answer:

Option B. Sodium

Explanation:

In the formation of NaCl, sodium loses and electron while chlorine receives the electron as illustrated below:

Na —> Na+ + e- ....... (1)

Cl + e- —> Cl- ......... (2)

Now, combining equation 1 and 2 we have:

Na + Cl + e- —> Na+ + Cl- + e-

Cancelling the electron from both side, we obtained:

Na + Cl —> Na+Cl-

From the above illustration, we see clearly that sodium loses electron

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What is reaction rate
zimovet [89]

Answer:The change in concentration of a reactant or product per unit time

Explanation:

6 0
3 years ago
Draw a physical model that shows the reaction of zinc metal and hydrochloric acid (hydrogen chloride).
Brilliant_brown [7]

Answer:

Zinc + Hydrochloric Acid Zinc Chloride and Hydrogen Gas

Zn + 2HCI - ZnCl2 + H2

Explanation:

Be sure to label your model to clearly show how you are representing the atoms

3 0
2 years ago
4. Why can't the subscripts be changed in a chemical equation in chemistry
neonofarm [45]
If you change the subscripts it would change the reactants or products and then you would be solving a different formula, you would change what the chemical is
4 0
3 years ago
1) How many moles are in 4.0x10^24 atoms?
-Dominant- [34]

Answer:

<h2>6.64 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{4 \times  {10}^{24} }{6.02 \times  {10}^{23} }   \\  = 6.644518...

We have the final answer as

<h3>6.64 moles</h3>

Hope this helps you

3 0
3 years ago
Consider the bonds in iron(III) oxide. Are the bonds more ionic or more covalent?
kvv77 [185]
<span>the bonds in iron(III) oxide are more ionic</span>
4 0
3 years ago
Read 2 more answers
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