Answer : The diatomic molecule of chlorine, Cl₂, is held together by a SINGLE covalent bond.
Covalent Bond :
It is type of chemical bond, which is formed by sharing of electron between atoms . The covalent bond is formed between two non metals . The valance electron are shared to form the bond . The shared electrons are known as BONDING electron pair and the electron pair which do not take part in bonding are known as NON- BONDING electron pair. Example : O₂ , H₂ , H₂O, NH₃ etc .
Formation of covalent bond in Cl₂ :
Chlorine is present in group 17 in p block , It is a non metal .
The electronic configuration of Cl is : 1s² 2s² 2p⁶ 3s² 3p⁵ .
Since the outer shell is n= 3 , which has 7 electrons in it , hence Cl has 7 valence electrons in it .
From electronic configuration , it can be seen that Cl need 1 electron to complete its octet (3s² 3p⁶ ). Hence when two Cl atoms come close they share one-one electron with each other (as shown in image ) .
Now the octet of both the atom are complete and they are in stable state together .
When both Cl atom share one e⁻ , there is a bond formed between Cl atoms . One bond consists of 2⁻ . Hence in Cl₂ SINGLE covalent bond present .
Cl + Cl -> Cl₂
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Answer:
Oxygen is oxidized and hydrogen is reduced.
Explanation:
Let's consider the redox reaction during the electrolysis of water in an electrolytic cell.
2 H₂O ⇒ 2 H₂ + O₂
The corresponding half-reactions are:
2 e⁻ + 2 H₂O ⇒ H₂ + 2 OH⁻
2 H₂O ⇒ O₂ + 4 H⁺ + 4 e⁻
Oxygen is oxidized since its oxidation number increases from -2 to 0.
Hydrogen is reduced since its oxidation number decreases from +1 to 0.
Answer:
<span> Its location is in the nucleus, because the particle is a proton or a neutron.</span>
Answer:
so 0.15 moles X 22.4 dm3/mole=3.36 dm3. Next we find the moles of hexane combusted, and then the moles of CO2. Finally, we find the volume of CO2 using the fact that at STP, 1 mole of gas = 22.4 dm3.