Answer:
0.800 mol of O2
Explanation:
<em>Calculate the moles of oxygen produced by the reaction of 0.800mol of carbon dioxide.</em>
The balanced equation for the reaction is given as;
6CO2 + 6H2O → C6H12O6 + 6O2
From the reaction;
6 mol of CO2 produces 6 mol of O2
0.0800 mol of CO2 would produce x mol of O2
6 = 6
0.0800 = x
Solving for x;
x = 6 * 0.800 / 6
x = 0.800 mol
The chemical reaction would be expressed as follows:
HBr + LiOH = LiBr + H2O
We are given the volumes and corresponding concentration to be used for the reaction. We use these values to solve for the concentration of the other reactant. We do as follows:
0.253 mol LiOH / L solution ( 0.01673 L ) ( 1 mol HBr / 1 mol LiOH ) = 0.00423 HBr needed
Concentration of HBr =0.00423mol / .010 L = 0.423 M HBr
Answer:
a) 3.98 x 10^-10
Explanation:
Hello,
In this case, for the given pH, we can compute the concentration of hydronium by using the following formula:
![pH=-log([H^+])](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29)
Hence, solving for the concentration of hydronium:
![[H^+]=10^{-pH}=10^{-9.40}\\](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-pH%7D%3D10%5E%7B-9.40%7D%5C%5C)
![[H^+]=3.98x10^{-10}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D3.98x10%5E%7B-10%7DM)
Therefore, answer is a) 3.98 x 10^-10
Best regards.
Answer:
Explanation:
This is a bond with reacts with metal's
The balanced net reactiion for the following half cells will be
Sn + Cr²⁺ ---> Sn²⁺ + Cr
<h3>What are
Half cells ?</h3>
A half cell is one of the two electrodes of an electrochemical cell.
An electrochemical cell comprises two half cells, where every half cell contains an electrode and an electrolyte.
A salt bridge or direct contact is needed to connect two half cells.
The balanced net reactiion for the given half cells will be
Sn + Cr²⁺ ---> Sn²⁺ + Cr
Learn more about Half cell here ;
brainly.com/question/1313684
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