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Hoochie [10]
1 year ago
8

the rate of a reaction increases when a catalyst has been added to the reaction mixture. the catalyst a) increases the kinetic e

nergy of the reactants. b) decreases the rate of the reverse reaction. c) increases the number of collisions between reactants. d) alters the enthalpy of reaction. e) provides a new mechanism for the reaction to proceed by.
Chemistry
1 answer:
Karolina [17]1 year ago
8 0

The rate of  the reaction increases when a catalyst has been added to the reaction mixture by e) providing a new mechanism for the reaction to procced by

Catalyst, in chemistry, a substance that speeds up a reaction without itself being consumed. Enzymes are natural catalysts responsible for many important biochemical reactions.

Most solid catalysts are oxides, sulfides, halides of metals or metallic elements, and metalloid elements boron, aluminum and silicon. Gas and liquid catalysts are usually used in pure form or in combination with suitable carriers or solvents. Solid catalysts are usually dispersed in another material known as a catalyst support.

Learn more about the catalyst in

brainly.com/question/28813725

#SPJ4

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10 points) Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, a
IceJOKER [234]

Answer:

The over all reaction :

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

Explanation:

Reduction at cathode :

Fe^{3+}(aq)+e^-\rightarrow Fe^{2+}(s)..[1]  

E^o_{Fe^{3+}/Fe^{2+}}=0.771 V

Reduction potential of Fe^{3+} to Fe^{2+}=0.771 V

Oxidation at anode:

Pb(s)\rightarrow Pb^{2+}(aq)+2e^-.[2]

E^o_{Pb^{2+}/Pb}=-0.126 V

Reduction potential of Pb^{3+} to Pb=-0.126 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

E^o_{cell}=E^o_{Fe^{3+}/Fe^{2+}}-E^o_{Pb^{2+}/Pb}

=0.771 V-(-0.126 )=0.897 V

The over all reaction : 2 × [1] + [2]

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

7 0
4 years ago
What distinguishes a mixture from an impure substance?
Leno4ka [110]

<u>Answer:</u> Mixture can be separated into its components but impure substance cannot be separated into components.

<u>Explanation:</u>

A mixture is defined as a combination of two or more different substances in which the component substances are individually distinct. The substances can be separated by physical processes. The separation dos not involve any chemical process because no new substance is being formed.

Impure substance is defined as a substance which can be mixture of elements, compounds or elements and compounds. The substances cannot be separated by physical means but can only be separated by chemical means.

3 0
3 years ago
Plz help I’m getting timed
valkas [14]

the answer is organism

5 0
3 years ago
Read 2 more answers
Which statement about the diagram, if electrons flow from
9966 [12]

The true statement is that the metal on the right oxidizes more easily than the one on the left.

<h3>What is metal oxidization?</h3>

Metal oxidation is known to often occur if an ionic chemical reaction is said to take place on a metal's surface at the presence of oxygen.

Note that Electrons often move from the metal to the oxygen molecules in course of this  process and as such The true statement is that the metal on the right oxidizes more easily than the one on the left.

Learn more about metal  from

brainly.com/question/1387159

#SPJ1

5 0
2 years ago
Which element would you expect to form an ionic compound when combined with bromine (Br)?
daser333 [38]
Ionic bond is formed due to the transfer of electrons from one atom to another so that all atoms involved in the bond would become stable (with 8 electrons in the outermost level)

Now, for bromine, it has 35 electrons. This means that bromine has 7 valence electrons in the outermost level. Therefore, bromine needs to gain one electron in order to become stable.

Bromine can react with elements from:
group 1: each element in group 1 needs to lose one electron to become stable. Therefore, one bromine atom can form an ionic bond when combined with an atom of an element from group 1 (element in group 1 loses its electron for bromine atom).
group 2: each element in group 2 needs to lose two electrons to become stable. Therefore, two bromine atoms can form ionic bonds when combined with an atom of an element from group 2 (element in group 2 loses two electrons, one for each bromine atom).
group 3: each element in group 3 needs to lose three electrons to become stable. Therefore, three bromine atoms can form ionic bonds when combined with an atom of an element from group 1 (element in group 3 loses three electrons, one for each bromine atom).

Since no choices are given , I cannot tell the exact choice. But the correct one would be the element from either group 1 , 2 or 3.
3 0
3 years ago
Read 2 more answers
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