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belka [17]
2 years ago
7

An angle of 200° is a/an angle.

Chemistry
1 answer:
anastassius [24]2 years ago
7 0

Answer:

Reflex angle

Explanation:

Angles that are greater than 180 degrees but less than 360 degrees have a special name: reflex angles.

Here, we see that 200 degrees is indeed between 180 and 360, which means it qualifies as a reflex angle.

The answer is thus reflex angle.

<em>~ an aesthetics lover</em>

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How many moles of MgO are produced when .250 mol of Mg reacts completely with O2
nignag [31]

Answer:

0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂

Explanation:

In first place, the balanced reaction between Mg and O₂ is:

2 Mg + O₂ ⇒ 2 MgO

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactants and products participate in the reaction:

  • Mg: 2 moles
  • O₂: 1 mole
  • MgO: 2 moles

Then you can apply the following rule of three: if by reaction stoichiometry 2 moles of Mg produce 2 moles of MgO, 0.250 moles of Mg, how many moles of MgO will they form?

moles of MgO=\frac{0.250 moles of Mg*2 moles of MgO}{2 moles of Mg}

moles of MgO= 0.250

<u><em>0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂</em></u>

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3 years ago
What is Chemistry and how do you relate in real life?
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Foxplain the term hybridizatim​
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Answer:

Showing results for explain the term hybridization​

Search instead for foxplain the term hybridization​

Image result for explain the term hybridization​

In chemistry, orbital hybridisation (or hybridization) is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory.

Explanation:

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Sulfur dioxide gas (SO2) and oxygen gas (O2) react to form the liquid product of sulfur trioxide (SO3). How much sulfur dioxide
taurus [48]
1) Balanced chemical equation:

2SO2 (g) +  O2 (g) -> 2SO3 (l)

2) Molar ratios

2 mol SO2 : 1 mol O2 : 2 mol SO3

3) Convert 6.00 g O2 to moles

number of moles = mass in grams / molar mass

number of moles = 6.00 g / 32 g/mol = 0.1875 mol O2.

4) Use proportions with the molar ratios

=> 2 moles SO2 / 1 mol O2 = x / 0.1875 mol O2

=> x = 0.1875 mol O2 * 2 mol SO2 / 1 mol O2 = 0.375 mol SO2.

5) Convert 0.375 mol SO2 to grams

mass in grams = number of moles * molar mass

molar mass SO2 = 32 g/mol + 2*16 g/mol = 64 g/mol

=> mass SO2 = 0.375 mol * 64 g / mol = 24.0 g

Answer: 24.0 g of SO2 are needed to react completely with 6.00 g O2.
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stellarik [79]

Answer:

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