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Amanda [17]
4 years ago
7

What is fabric paint used for?

Chemistry
2 answers:
lawyer [7]4 years ago
7 0

Answer:

it can be usefull in many ways

Explanation:

stira [4]4 years ago
4 0
Fabric painting is a great way to add new life to plain old t-shirts, boring upholstery, or any bland fabric that needs a boost. Mastering the art of fabric painting allows you to become your own fashion or interior designer by painting your ideas into existence
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The following substances dissolve when added to water. Classify the substances according to the strongest solute-solvent interac
Montano1993 [528]

Answer: HF-dipole- dipole interaction

CH3OH- dipole-dipole interaction

CaCl2- ion-ion interaction

Explanation:

Both CH3OH and HF possess permanent dipoles which interact with water leading to the dissolution of the above named substances. Remember that water also possesses a permanent dipole. Which can interact with the dipoles on other polar molecules. CaCl2 is purely ionic and interacts with water via ion-dipole mechanism.

8 0
4 years ago
The best method for seperating a salt from water is
abruzzese [7]

Answer:1 Boiling

Explanation:

Salt (Solute) + water (solvent) = Solution.

Salt dissolves in water, therefore, the only way to recover the salt is by boiling (evaporation) the solution.

6 0
3 years ago
Read 2 more answers
The equilibrium constant Kp for the reaction I2(g) + Br2(g) ⇀↽ 2 IBr(g) + 11.7 kJ is 280 at 150◦C. Suppose that a quantity of IB
mixas84 [53]

Answer:

\large \boxed{\text{0.0120 atm }}

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

      Kp = 280

p(IBr) = 0.200 atm

1. Set up an ICE table.

Let p = the initial pressure of IBr. Then

\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} &  &  \\0 & & 0 & & p & & \\+x &   & +x  & & -2x &   &\\x &   & x} &   & 280 & & \\\end{array}

2. Calculate p(I₂)

\begin{array}{rcl}K_{\text{p}}&=&\dfrac{p_{\text{IBr}}^{2}} {p_{\text{I}_2}^{2}}\\\\280&=&{\dfrac{0.200^{2}}{x^{2}}&&\\\\280x^{2} & = &0.0400\\x^{2} & = &\dfrac{0.0400}{280 }\\\\& = & 1.429 \times 10^{-4}\\x & = & \textbf{0.0120 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.0120 atm }}$}}

Check:

\begin{array}{rcl}{\dfrac{0.200^{2}}{0.0120^{2}}}&=&280\\\\280& =& 280\\\end{array}

8 0
3 years ago
Calculate the volume of each of the following gases at STP
kherson [118]
For Ar :

1 mol ------------ 22.4 L ( at STP )
7.6 mol ---------- x L 

x = 7.6 * 22.4

x = 170.24 L
-----------------------------------------------------------------
For C2H3:

1 mol ------------ 22.4 ( at STP)
0.44 mol --------- y L

y = 0.44 * 22.4

y = 9.856 L

hope this helps !.



7 0
4 years ago
Ignore, question was removed
djverab [1.8K]
Rip bro but I need the point
6 0
3 years ago
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