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zimovet [89]
3 years ago
8

HELP ASAP!! BRAINLIEST!! If you added a 15.00 piece of solid Cu to an aqueous solution of silver nitrate, the silver would be re

placed in a single replacement reaction forming aqueous copper(II) nitrate and solid silver. How much silver is produced if 15.00 g of Cu is added to the solution of excess silver nitrate?
1. Determine the moles of Ag produced:
2. Convert moles Ag to grams of Ag produced:
Chemistry
1 answer:
klasskru [66]3 years ago
5 0
Can you give me more information in order to answer this?
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When crude oil get extracted from well, salt water and some other stuff needs to be removed before oil can be sued in the car


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. Which type of energy is involved in the operation of simple machines?
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Input an output  energy
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Butane is also a molecular compound. what is its formula? how many atoms does it contain?
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The formula of butane is C4H10 but I don't how many atoms it contains though
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In the manufacture of paper, logs are cut into small chips, which are stirred into an alkaline solution that dissolves several o
Kitty [74]

Answer:

The estimated feed rate of logs is 14.3 logs/min.

Explanation:

The product of the process is 2000 tons/day of dry wood pulp, of 85 wt% of cellulose. That represents (2000*0.85)=1700 tons/day of cellulose.

That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.

Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.

To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.

V=V_c+V_w\\\\M/\rho=M_c/\rho_c+Mw/\rho_w\\\\M/\rho=0.55*M/\rho_c+0.45*M/\rho_w\\\\1/\rho=0.55/\rho_c +0.45/\rho_w\\\\0.55/\rho_c=1/\rho-0.45/\rho_w\\\\0.55/\rho_c=1/(0.64*\rho_w)-0.45/\rho_w=(1/\rho_w)*(\frac{1}{0.64}-\frac{0.45}{1}  )\\\\0.55/\rho_c=1.1125/\rho_w\\\\\rho_c=\frac{0.55}{1.1125}*\rho_w= 0.494*\rho_w

The specific gravity of the wood chips is 0.494.

The average volume of a log is

V_l=(\pi*D^{2} /4)*L=(3.1416*\frac{8^{2}  \, in^{2} }{4} )*9ft*(\frac{12 in}{1ft})= 21714 in^{3}=12.57 ft^{3}

The weight of one log is

M=\rho*V=0.494*\rho_w*12.57  ft^{3}\\\\M=0.494*62.4\frac{lbm}{ft^{3} }*12.57ft^{3}\\\\M=387.5lbm

To provide 3617 ton/day of wood chips, we need

n=\frac{supply}{M_{log}}=\frac{3617 tons/day}{387.5 lbm}*\frac{2204lbm}{1ton}\\\\n=20573 logs/day=14.3 logs/min

The feed rate of logs is 14.3 logs/min.

7 0
3 years ago
Read 2 more answers
What would happen if you touched a flask during an endothermic reaction?
max2010maxim [7]
The heat from your hand would be absorbed by the (assumed) colder flask, since an endothermic reaction means that the reaction requires an absorption of heat as opposed to an exothermic reaction, which releases heat.
5 0
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