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san4es73 [151]
4 years ago
11

Select the answer that CANNOT be used to fill in the blank in the following sentence:

Chemistry
1 answer:
Mashcka [7]4 years ago
6 0

Answer:

3. move more quickly

Explanation:

...................

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A student carefully drops a 9.0 g solid Zn pellet initially at 50.0°C into an insulated cup containing 30.0 g of water at 27.8°C
jekas [21]

Answer: choice B

Explanation: Heat flows from high to low. After you convert the Celsius into kelvin the Zn pellet has 323K and the water has 301K which results the transfer of the heat energy of the pallet to the water. ( you don’t have to convert, but it just make it easier) hope this helped you :)

3 0
3 years ago
Read 2 more answers
Which ion has the same electron configuration as an atom of He?
mariarad [96]

Answer;

H- (negatively charged hydrogen ion)

Explanation;

The hydrogen ion has the same electron configuration as an atom of Helium. -Hydrogen ion is formed when a hydrogen atom loses or gains an electron. A positively charged ion is formed when hydrogen atom loses an electron (remaining with zero electrons) while a negatively charged ion (H-) is formed when a hydrogen atom gains an electron thus having 2 electrons.

-Helium atom has two electrons, therefore, it is similar with an negatively charged hydrogen.

3 0
3 years ago
Read 2 more answers
A solution is to be prepared with a sodium ion concentrationof
Lina20 [59]

Answer : The mass of sodium sulfate needed is 5.7085 grams.

Explanation : Given,

Concentration of sodium ion = 0.148 mol/L

Volume of solution = 2.29 L

Molar mass of sodium sulfate = 142 g/mole

First we have to determine the moles of sodium ion.

\text{Concentration of sodium ion}=\frac{\text{Moles of sodium ion}}{\text{Volume of solution}}

0.184mol/L=\frac{\text{Moles of sodium ion}}{2.29L}

\text{Moles of sodium ion}=0.08035mole

Now we have to calculate the moles of sodium sulfate.

The balanced chemical reaction will be,

Na_2SO_4\rightarrow 2Na^++SO_4^{2-}

As, 2 moles of sodium ion produced from 1 moles of Na_2SO_4

So, 0.08035 moles of sodium ion produced from \frac{0.08035}{2}=0.040175 moles of Na_2SO_4

Now we have to calculate the mass of sodium sulfate.

\text{Mass of }Na_2SO_4=\text{Moles of }Na_2SO_4\times \text{Molar mass of }Na_2SO_4

\text{Mass of }Na_2SO_4=0.040175mole\times 142g/mole=5.7085g

Therefore, the mass of sodium sulfate needed is 5.7085 grams.

3 0
4 years ago
3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O
Ksivusya [100]

Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

<h3 /><h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:  

  • Cu: 3 moles
  • HNO₃: 8 moles
  • Cu(NO₃)₂: 3 moles
  • NO: 2 moles
  • H₂O: 4 moles

<h3>Amount of moles of NO produced</h3>

It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

amount of moles of NO=\frac{27 moles of HNO_{3} x 2 moles of NO}{8 moles of HNO_{3}}

<u><em>amount of moles of NO= 6.75 moles</em></u>

In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

Learn more about reaction stoichiometry:

<u>brainly.com/question/11999193</u>

<u>brainly.com/question/15111313?referrer=searchResults</u>

<u>brainly.com/question/9926203?referrer=searchResults</u>

<u>brainly.com/question/6061451?referrer=searchResults</u>

4 0
3 years ago
18.74 g of P4 is reacted with 9.6 g of Cl2 balanced is P4 (s) + 6 Cl2 (g) → 4 PCl3 (l) how many PlC3 can I make?
Yanka [14]

P4(s) + 6Cl2(g) → 4PCl3(l)

n P4 = m P4 / Mr P4

n P4 = 18.74 / 123.88

n P4 = 0.151 mol

n Cl2 = m Cl2 / Mr Cl2

n Cl2 = 9.6 / 70.9

n Cl2 = 0.135 mol

Cl2 act as <u>limiting reactant</u>

n PCl3 = (coef. PCl3)/(coef. Cl2) • n Cl2

n PCl3 = (4/6) • 0.135

n PCl3 = 0.09 mol

m PCl3 = n PCl3 • Mr PCl3

m PCl3 = 0.09 • 137.33

m PCl3 = 12.36 gr

3 0
2 years ago
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