Select the answer that CANNOT be used to fill in the blank in the following sentence:

What is the mass of the light bulb and paperclips together? a. 250.1 g b. 246.0 g c. 251.0 g d. 205.10 g

ololo11 [35]

251.0 is the correct mass of the light bulb and paperclips together.

Mass is a physical body's total amount of matter. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured by this term. The strength of an object's gravitational pull to other bodies is also influenced by its mass. The kilogram serves as the SI's fundamental mass unit.

For a body, mass is constant. Mass can be calculated using the formula: mass = volume density. A mass's weight is a measurement of the gravitational force at work on it. The kilogram is the SI unit of mass.

The mass of the substance will therefore be calculated as follows: MASS OF A SUBSTANCE = VOLUME DENSITY.

So finally we can say that the mass of the light bulb and paperclips together is 250.1g.

To know more about Mass please click here : brainly.com/question/19385703

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4 0

1 year ago

In the mirror diagram shown, Which is the normal?

o-na [289]

Answer:

C

Explanation:

always look for the line that is perpendicular to the surface

7 0

3 years ago

Read 2 more answers

Ammonia is a principal nitrogen fertilizer. It is prepared by the reaction between hydrogen and nitrogen. 3H2(g) + N2(g) → 2NH3(

sergey [27]

Answer:

Explanation:

The equation of the reaction is given as:

3H₂ + N₂ → 2NH₃

Given parameters:

Number of moles of NH₃ = 8moles

Number of moles of H₂ = ?

Number of moles of N₂ = ?

Solution

From the balanced reaction equation, we can establish some mole ratios that would help solve the problem:

To find the number of moles of H₂;

The equation shows that:

2 moles of NH₃ were produced using 3 moles of H₂

therefore: 8 moles of NH₃ will be produced by $\frac{8 x 3}{2}$ = 12moles

So, 12 moles of hydrogen gas will react to give 8 moles of ammonia.

To find the number of moles of N₂

The equation shows that:

2 moles of NH₃ were produced from 1 mole of N₂

8 moles of NH₃ would be produced from $\frac{8 x 1}{2}$ = 4moles of Nitrogen gas

Therefore, 4moles of nitrogen gas would be produced

6 0

3 years ago

Whenever fa body object is in motion there is always ____ to oppose the motion

insens350 [35]

Friction. Imagine rubbing your hand against a carpet and how it gets hot even though you are pushing it afar. That is friction.

3 0

3 years ago

Find the potentials of the following electrochemical cell:

melomori [17]

Answer: 0.18 V

Explanation:-

$Cd/Cd^{2+}(0.10M)//Ni^{2+}(0.50M)?Ni$

Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

$E^0_(Cd^{2+}/Cd)$ =-0.40V[/tex]

$E^0_(Ni^{2+}/Ni)$ =-0.24V[/tex]

$Cd+Ni^{2+}\rightarrow Cd^{2+}+Ni$

Here Cd undergoes oxidation by loss of electrons, thus act as anode. nickel undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0=E^0_{[Ni^{2+}/Ni]}- E^0_{[Cd^{2+}/Cd]}$

$E^0=-0.24-(-0.40)=0.16V$

Using Nernst equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cd^{2+}]}{[Ni^{2+]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential = 0.16 V

$E_{cell}=0.16-\frac{0.0592}{2}\log \frac{[0.10]}{[0.5]}$

$E_{cell}=0.18V$

Thus the potential of the following electrochemical cell is 0.18 V.

6 0

3 years ago