Question

Tyson Gay's best time to run 100.0 meters was 9.69 seconds. What was his average speed during this run, in miles per hour? (3.281ft=1 m)(1 mile=5280 ft)

Answer 1

Answer:

Explanation:

distance, d = 100 m = 100 x 3.28 ft = 328 ft = 328 / 5280 miles = 0.062 miles

time, t = 9.69 second = 0.00269 hour

Average speed is defined as the ratio of total distance traveled to the total time taken.

Average speed = d / t = 0.062 / 0.00268

Average speed = 2.31 miles per hour.

Answer 2

Answer:

23.086 mile/h

Explanation:

Given,

Distance Tyson Gay run = 100 m

time of run, t = 9.69 s

average speed of the in mph = ?

Speed of the Gay = $\dfrac{distance}{time}$

$v = \dfrac{100}{9.69}$

     v = 10.32 m/s

1 m = 3.281 ft

10.32 m = 33.86 ft

1 mile = 5280 ft

1 ft = 1.8939 x 10⁻⁴ mile

33.86 ft/s = 6.413 x 10⁻³ miles/s

Speed of Tyson in mile/hr = 6.413 x 10⁻³ x 3600

                                           = 23.086 mile/h

Hence, speed of Tyson Gay's in mile/ hr is equal to 23.086 mph.