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alexandr1967 [171]
3 years ago
15

Tyson Gay's best time to run 100.0 meters was 9.69 seconds. What was his average speed during this run, in miles per hour? (3.28

1ft=1 m)(1 mile=5280 ft)
Physics
2 answers:
Kryger [21]3 years ago
6 0

Answer:

Explanation:

distance, d = 100 m = 100 x 3.28 ft = 328 ft = 328 / 5280 miles = 0.062 miles

time, t = 9.69 second = 0.00269 hour

Average speed is defined as the ratio of total distance traveled to the total time taken.

Average speed = d / t = 0.062 / 0.00268

Average speed = 2.31 miles per hour.

FinnZ [79.3K]3 years ago
4 0

Answer:

23.086 mile/h

Explanation:

Given,

Distance Tyson Gay run = 100 m

time of run, t = 9.69 s

average speed of the in mph = ?

Speed of the Gay = \dfrac{distance}{time}

v = \dfrac{100}{9.69}

     v = 10.32 m/s

1 m = 3.281 ft

10.32 m = 33.86 ft

1 mile = 5280 ft

1 ft = 1.8939 x 10⁻⁴ mile

33.86 ft/s = 6.413 x 10⁻³ miles/s

Speed of Tyson in mile/hr = 6.413 x 10⁻³ x 3600

                                           = 23.086 mile/h

Hence, speed of Tyson Gay's in mile/ hr is equal to 23.086 mph.

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Answer:

Yellow.

Explanation:

An object that reflects all the incidents colors of light will surely reflect off the color yellow, and when the reflected ray hits our eyes, we will perceive the object as yellow. The object that reflects off all colors appears to us as white. So if you want to make sure, then just shine yellow light on a white fabric and see what happens!

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Answer:

0.21486 mm

Explanation:

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Now,we are not given Φ but it can be expressed in terms of what we are given as; Φ = πdy/(λL)

Where;

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I = I_o•πdy/(λL)

We are given;

d = 0.05 mm = 0.5 × 10^(-3) m

λ = 540 nm = 540 × 10^(-9) m

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From earlier, we saw that;

I = I_o•πdy/(λL)

We have I/I_o = 0.5

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I/I_o = πdy/(λL)

Plugging in the relevant values;

0.5 = (π × 0.5 × 10^(-3) × y)/(540 × 10^(-9) × 1.25)

Making y the subject, we have;

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mass C * velocity C = mass D * velocity D

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6) use in the equation stated in the point 4)

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