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alexandr1967 [171]
3 years ago
15

Tyson Gay's best time to run 100.0 meters was 9.69 seconds. What was his average speed during this run, in miles per hour? (3.28

1ft=1 m)(1 mile=5280 ft)
Physics
2 answers:
Kryger [21]3 years ago
6 0

Answer:

Explanation:

distance, d = 100 m = 100 x 3.28 ft = 328 ft = 328 / 5280 miles = 0.062 miles

time, t = 9.69 second = 0.00269 hour

Average speed is defined as the ratio of total distance traveled to the total time taken.

Average speed = d / t = 0.062 / 0.00268

Average speed = 2.31 miles per hour.

FinnZ [79.3K]3 years ago
4 0

Answer:

23.086 mile/h

Explanation:

Given,

Distance Tyson Gay run = 100 m

time of run, t = 9.69 s

average speed of the in mph = ?

Speed of the Gay = \dfrac{distance}{time}

v = \dfrac{100}{9.69}

     v = 10.32 m/s

1 m = 3.281 ft

10.32 m = 33.86 ft

1 mile = 5280 ft

1 ft = 1.8939 x 10⁻⁴ mile

33.86 ft/s = 6.413 x 10⁻³ miles/s

Speed of Tyson in mile/hr = 6.413 x 10⁻³ x 3600

                                           = 23.086 mile/h

Hence, speed of Tyson Gay's in mile/ hr is equal to 23.086 mph.

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a driver travels 135 km, east in 1.5 h, stops for 45 minutes for lunch, and then resumes driving for the next 2.0 h through a di
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Answer:

v = 98.75 km/h

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The distance driver travels towards the east, d₂ = 215 km

The time period of the travel, t₁ = 2 h

The average speed of the vehicle before stopping

                                    v₁ = d₁/t₁

                                        = 135/1.5

                                       = 90 km/h

The average speed of vehicle after stopping

                                    v₂ = d₂/t₂

                                         = 215/2

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The total average velocity of the driver

                                      v = (v₁ +v₂) /2

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An automobile engineer found that the impact of a truck colliding at 14 km/h with a concrete pillar caused the bumper to indent
BlackZzzverrR [31]
Hello
Here we must use the equation of motion 
v^2 = u^2 + 2as; where v is final velocity, u is initial velocity, a is the acceleratoin and is the distance travelled.
We select this one because the time of collision is unknown to us.
We know the truck stopped so its final velocity is 0; thus v = 0.
Converting the initial velocity to SI units, we get 3.89 m/s.
The distance traveled, s, is 0.062 meters.
Inserting all of these values into the equation,
0 = (3.89)^2 + 2(a)(0.062)
and solving for a, we get a to be
-122.0 ms^(-2)
The negative sign indicates the acceleration is in the opposite direction to the initial motion, which means the truck decelerated. This is consistent with the given condition.
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