Answer:
Hope it helps for you :)))))
The formula to use is: I = (<span> ΔV / R )
Once you solve for R, your new formula would be: R= (</span><span> ΔV / I )
Plug in your values to get: R = (1.5V / .75A )
Finally, R = 2</span><span>Ω</span>
Answer:
External locus of control
Explanation:
External locus of control is an attitude people possess that makes them attribute their failures or successes to factors other than themselves. The opposite of this type of attitude is the Internal locus of control where the individuals take responsibility for the outcomes of their actions whether good or bad. One good thing about the external locus of control is that when the individuals with this characteristic record successes, they attribute it to others and this presents them as people with team spirit. However, when they record failures, they do not want to take the blame, but rather attribute it to others.
Fred exhibits an external locus of control because he attributed his speeding to other factors like the road signs and GPS instead of fully admitting that it was his fault.
Answer:
A. Aluminium
Explanation:
Buoyant force is simple terms refers to the weight of water displaced when an object is immersed in it. The higher the volume of an object, the higher the buoyant force.
From the problem, we have two metals of equal mass, aluminium and lead, of which lead is denser.
density =
Volume =
This means that the volume of each metal depends on the density, and for the fact that lead is denser , it will have a lower volume than aluminium which means Aluminium will have a greater buoyant force.
Answer:
4 m/s² down
Explanation:
We'll begin by calculating the net force acting on the object.
The net force acting on the object from the left and right side is zero because the same force is applied on both sides.
Next, we shall determine the net force acting on the object from the up and down side. This can be obtained as follow:
Force up (Fᵤ) = 15 N
Force down (Fₔ) = 25 N
Net force (Fₙ) =?
Fₙ = Fₔ – Fᵤ
Fₙ = 25 – 15
Fₙ = 10 N down
Finally, we shall determine the acceleration of the object. This can be obtained as follow:
Mass (ml= 2.5 Kg
Net force (Fₙ) = 10 N down
Acceleration (a) =?
Fₙ = ma
10 = 2.5 × a
Divide both side by 2.5
a = 10 / 2.5
a = 4 m/s² down
Therefore, the acceleration of the object is 4 m/s² down
