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kondor19780726 [428]
3 years ago
15

Which factors in the earth relationship to the sun make life on earth possible

Physics
1 answer:
erma4kov [3.2K]3 years ago
8 0

The sun warms the planet, drives the hydro logic cycle, and makes life on Earth possible. The amount of sunlight received on Earth's surface is affected by the reflectivity of the surface, the angle of the sun, the output of the sun, and the cyclic variations of Earth's orbit around the sun.

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Just two questions please answer.physics wave
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Find the unit vector in the direction of the resultant vector A=2i-3j+4k B=i+j+2k C=3i-2j+4k
shtirl [24]

Answer:

R = 6i - 4j + 10k

Explanation:

R = (2 + 1 + 3)i + (-3 + 1 - 2)j + (4 + 2 + 4)k

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The velocity of the wind relative to the water is crucial to sailboats. Suppose a sailboat is in an ocean current that has a vel
Brilliant_brown [7]

Answer:

Explanation:

We shall write the velocities given in vector form to make the solution easy.

The velocity of water with respect to earth that is waV(e) makes 30 degree with north or 60 degree with east so in vector form

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waV(e) = 1.1 i + 1.9 j

Similarly , velocity of wind with respect to earth that is wiV(e) , is making 50 degree with west or - ve of x axes so we cal write it in vector form as follows

wiV(e) =  - 4.5 cos 50 i - 4.5 sin 50 j

wiV(e) = - 2.89 i - 3.45 j

Now we have to calculate velocity of wind with respect to water that is

wiVwa

wiV( wa) = wiV ( e)+ eV(wa)

=  wiV( e)- waV(e)

- 2.89 i - 3.45 j - 1.1 i -  1.9 j

= - 3.99 i - 5.35 j

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6 0
3 years ago
What do nebulae have the most in common with?
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3 0
4 years ago
A proton is given an acceleration of 1.5x109 m/s² when it is placed in an electric field.
olga nikolaevna [1]

Answer:

The strength of the electric field is E=15.66\: N/C

Explanation:

Here the electric force is equal to Newton's second law.

F_{e}=ma

Let's recall that electric force is the electric field times the charge, so we have:

qE=ma

E=\frac{ma}{q} (1)

Where:

m is the proton mass

q is the proton charge

a is the acceleration        

Using the equation (1) we have:

E=\frac{1.67*10^{-27}1.5x10^{9}}{1.6*10^{-19}}

Therefore, the strength of the electric field is E=15.66\: N/C

I hope it helps you!

7 0
3 years ago
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