Answer:
vₓ = 0.566 m / s, W_total = 9.1 J
Explanation:
This exercise is a parabolic type movement, for the x axis where there is no acceleration
x = v t
vₓ = x / t
vₓ = 0.34 / 0.6
vₓ = 0.566 m / s
the work done is
X axis
In this axis there is no acceleration, therefore the sum of the forces is zero and since the work is the force times the distance, we conclude that the lock in this axis is zero.
W₁ = 0
Y axis
in this axis the force that exists is the force of gravity, that is, the weight of the body
W₂ = Fy y
W₂ = mg and
W₂ = m 9.8 0.70
W₂ = m 9.1
the work is a scalar for which we have to add the quantities obtained
W_total = W₁ + W₂
W_total = 0 + 9.1 m
W_total = 9.1 m
In order to complete the calculation, the mass of the body is needed if we assume that the mass is m = 1
W_total = 9.1 J
<span>Energy is calculated by molecule dividing energy by mole by Avogadro's number (6.022*10^23)
941kJ=9.41*10^5 J
so energy by molecule
E= 9.41*10^5/6.022*10^23=1.563*10^-18 J
Wavelength (w) given by E=hc/w
where, E = energy
h = planks constant (6.6262 x 10-34 J·s)
c = speed of light (3 x 10^8 m/s )
So,
w= hc/E
= (6.6262*10^-34)*(3*10^8) /1.563*10^-18
= 127.2 Nm
Longest wavelength of radiation =127.2 Nm</span>
F = ma
F 1500N
m = 100 kg
1500 = 100 * a
Solve for a.
Answer:
1.6 m/s2
Explanation:
Let 
be the gravitational acceleration of the moon. We know that due to the law of energy conservation, kinetic energy (and speed) of the rock when being thrown upwards from the surface and when it returns to the surface is the same. Given that stays constant, we can conclude that the time it takes to reach its highest point, aka 0 velocity, is the same as the time it takes to fall down from that point to the surface, which is half of the total time, or 4 / 2 = 2 seconds.
So essentially it takes 2s to decelerate from 3.2 m/s to 0. We can use this information to calculate
So the gravitational acceleration on the Moon is 1.6 m/s2
