The answer is A. conduction
Answer:For example, standard atmospheric pressure (or 1 atm) is defined as 101.325 kPa. The millibar, a unit of air pressure often used in meteorology, is equal to 100 Pa. (For comparison, one pound per square inch equals 6.895 kPa.)
Explanation:A pascal is a pressure of one newton per square metre, or, in SI base units, one kilogram per metre per second squared.
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Answer:
Explanation:
Given that the angular velocity is constant.
The actual weight is W = 549N
The ride apparent weight is
W' = 1.5N
Apparent weight at the top of the ride?
Using newton second law of motion
ΣF = m•ar
ar is the radial acceleration
N — W = —m•ar
N = W —m•ar
N = mg —m•ar
N = m(g—ar)
The apparent weight is equal to the normal
W'(top) = N = m(g—ar)
W'(top) = m(g—ar)
W'(top) = mg —m•ar
We know that the actual weight is
W=mg
Also, the apparent weight is
W' = m•ar
Then
W'(top) = Actual weight - apparent
W'(top) = 549—1.5
W'(top) = 547.5 N
For a circular orbit, the force of gravity must equal the centripetal force on the satellite.

G gravitational constant
M mass of earth
m mass of satellite
R radius of orbit
the mass m cancels: