Question

A proton is given an acceleration of 1.5x109 m/s² when it is placed in an electric field.

Answer 1

Answer:

The strength of the electric field is $E=15.66\: N/C$

Explanation:

Here the electric force is equal to Newton's second law.

$F_{e}=ma$

Let's recall that electric force is the electric field times the charge, so we have:

$qE=ma$

$E=\frac{ma}{q}$ (1)

Where:

m is the proton mass

q is the proton charge

a is the acceleration        

Using the equation (1) we have:

$E=\frac{1.67*10^{-27}1.5x10^{9}}{1.6*10^{-19}}$

Therefore, the strength of the electric field is $E=15.66\: N/C$

I hope it helps you!