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4 years ago

How can I use models to help me divide? .d.

Mathematics

2 answers:

sdas [7]4 years ago

6 0

Division is multiplications opposites so for example if u have 12 crayons and u divide that by 6 you get 2 crayons.

givi [52]4 years ago

3 0

Use the model for an example like if u have 7 blocks put them in 2 groups how many are in each group and how many are left over

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What type of angle pair are 2 and 5 in the figure below

kvv77 [185]

Answer:

VERTICALLY OPPOSITE ANGLES

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3 years ago

The dimensions of a rectangular prism are given in the net shown. 7 in. x4 . 3 in. 5 in. 3 in.x 4 5 in. What is the total surfac

swat32

The total surface area of any given net of a rectangular prism = area of each rectangular face.

<h3>What is the Total Surface Area of a Rectangular Prism?</h3>

If we are given the net of a rectangular prism, the total surface area of the rectangular prism is the area of each rectangular face all summed together.

The image of the net of the rectangular prism is missing, however, let's assume the image attached below is the net of the prism.

Therefore, the total surface area of the rectangular prism = area of each rectangular face = 20 + 8 + 40 + 8 + 20 + 40 = 96 cm².

Learn more about the rectangular prism on:

brainly.com/question/1015291

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2 years ago

A train travels 616 miles at a speed of 55 miles per hour. Use the equation d equals r t to find the time the train travels.

MatroZZZ [7]

Answer:

t=11.2

Step-by-step explanation:

d=rt

616=55*t

t=11.2

5 0

3 years ago

Is the given number the solution of the equation

Ipatiy [6.2K]

For #2 it is. #4 it isn’t. #6 it isn’t.

6 0

3 years ago

Read 2 more answers

Calculate the limit of the function with L'Hospital rule

mr_godi [17]

Answer:

L=24

Step-by-step explanation:

L'Hopital's Rule for Evaluating Limits:

Rule is that if $\lim_{x \to a} \frac{f(x)}{g(x)}$ takes $\frac{0}{0}$ or $\frac{\infty}{\infty}$ form, then,

$\lim_{x \to a} \frac{f(x)}{g(x)}= \lim_{x \to a} \frac{f'(x)}{g'(x)}$

where $f'(x)=\frac{df(x)}{dx}$ and $g'(x)=\frac{dg(x)}{dx}$

Now coming to the problem,

$L= \lim_{x \to \frac{\pi}{6} } \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3} )}$

Here $f(x)=cot^{3}x-3cotx$ and $g(x)=cos(x+\frac{\pi}{3} )$

Substituting $x=\frac{\pi}{6}$ in f(x) and g(x),

$f(\frac{\pi}{6})=cot^{3}\frac{\pi}{6}-3cot\frac{\pi}{6}\\=3\sqrt{3}-3\sqrt{3}\\ =0$

$g(\frac{\pi}{6})=cos(\frac{\pi}{6}+\frac{\pi}{3})\\=cos\frac{\pi}{2}\\=0$

Since L takes the form $\frac{0}{0}$ , using l'hopital's rule

$L= \lim_{x \to \frac{\pi}{6}} \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3})}= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}x(-cosec^{2}x)-3(-cosec^{2}x)}{-sin(x+\frac{\pi}{3})}$

now substituting $x=\frac{\pi}{6}$ ,

$L= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}\frac{\pi}{6}(-cosec^{2}\frac{\pi}{6})-3(-cosec^{2}\frac{\pi}{6})}{-sin(\frac{\pi}{6}+\frac{\pi}{3})}\\=\frac{3*3^{2}(-2^{2})+3(2^{2})}{-1}\\=24$

6 0

3 years ago