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Sergeu [11.5K]
3 years ago
7

How much kinetic energy is possessed by a 12 kg remote controlled car that is traveling with a speed of 5 m/s?

Mathematics
2 answers:
beks73 [17]3 years ago
8 0

Answer:

150 joules.

Step-by-step explanation:

Kinetic Energy of a moving object = 1/2 m v^2.

So it is 1/2 * 12 * 5^2

= 150 J.

Marianna [84]3 years ago
7 0

Answer: 150 Kgm^{2}/s^{2}

Step-by-step explanation:

K.E = \frac{1}{2}mv^{2}

K.E =  \frac{1}{2} X 12 X 25

K.E = 150

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Need to find the sum of 50
Bumek [7]

Answer:

4600

Step-by-step explanation:

This is an arithmetic sequence with common difference d between consecutive terms.

d = - 2 - (- 6) = 2 - (- 2) = 6 - 2 = 4

The sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2}[ 2a + (n - 1)d ]

where a is the first term

here a = - 6, d= 4 and n = 50, hence

S_{50} = \frac{50}{2} [ (2 × - 6) + (49 × 4) ]

                           = 25 ( - 12 + 196 )

                           = 25 × 184

                           = 4600

6 0
3 years ago
Pleas help me, please explain how you got your answer :)​
Verdich [7]

Answer:

im not sure but i think its e,c,f

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Shandra's parents put $1,500 in her bank account for college tuition. At an interest rate
gavmur [86]

Answer:

$6,427.99

Step-by-step explanation:

-We first find the effective annual interest rate as follows:

i_m=(1+i/m)^m-1\\\\=(1+0.0825/2)^2-1\\\\=0.084202

#We the use this rate to find the compounded amount after 18 years:

A=P(1+i_m)^n\\\\=1500(1.084202)^{18}\\\\=6427.99

Hence, the amount after 18 years is $6,427.99

5 0
3 years ago
Find the product mentally. (ab + 3)2 ab2 + 6ab + 9 2ab + 6 a2b2 + 6ab + 9
Contact [7]

I think it's a^2 b^2 + 6ab + 9

4 0
3 years ago
Read 2 more answers
Two circles with different radii have chords AB and CD, such that AB is congruent to CD. Are the arcs intersected by these chord
emmainna [20.7K]

The arcs intersected by these chords are not congruent.

Given that two circles with different radii have chords AB and CD, such that AB is congruent to CD.

Let r₁ and r₂ be the radii of two different circles with centers O and O' respectively.

Assuming that the each of the ∠АОВ  and ∠CO'D is less than or equal to π.

Then, we have isosceles triangle AOB and CO'D such that,

AO = OB = r₁,

CO' = O'D = r₂,

Let us assume that r₁< r₂;

We can see that arc(AB) intersected by AB is greater than arc(CD), intersected by the chord CD;

arc(AB) > arc(CD)      .......(1)

Indeed,

arc(AB) = r₁ angle (AOB)

arc(CD) = r₂ angle (CO'D)

So, we have to prove that ;

∠AOB >∠CO'D       ......(2)

Since each angle is less than or equal to π, and so

∠AOB/2  and ∠CO'D/2 is less than or equal to π

it suffices to show that :

tan(AOB/2) >tan(CO'D/2) ......(3)

From triangle AOB :

tan(AOB/2) = AB/(2*r₁)

tan(CO'D/2) = CD/(2*r₂)

Since AB = CD and r₁ < r₂ (As obtained from the result of (3) ), therefore, arc(AB) > arc(CD).

Hence, for two circles with different radii have chords AB and CD, such that AB is congruent to CD but the arcs intersected by these chords are not congruent.

Learn more about congruent from here brainly.com/question/1675117

#SPJ1

6 0
1 year ago
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