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3 years ago

A house can be build using 15 panels,how many houses can be build using 1000 panels

Mathematics

2 answers:

artcher [175]3 years ago

8 0

Answer: 67

Step-by-step explanation:

I think this could be solved using division. 1000 / 15 is 66.66666, but I would round that to 67.

liq [111]3 years ago

4 0

The answer is 66 because there cannot be fractions of a house

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Find the volume of a rectanglular prism if the length is x and the width is x^2 and the height is 5x^2 +4x+1. Use the formula v=

My name is Ann [436]

Answer:

The volume = $5x^{5}+4x^{4}+x^{3}$

Step-by-step explanation:

* The rule of the volume of the rectangular prism:

- the volume of any prism = base area × height

∵ The base of the rectangular prism is rectangle

∵ Area any rectangle = Length × Width = l × w

∴ The volume of the rectangular prism = l × w × h

* In the problem:

∵ l = x , w = x² , h = 5x² + 4x + 1

∴ The volume = (x)(x²)(5x² + 4x + 1)

* We will simplify it

- Multiply x by x² and then multiply the answer by the bracket

∵ x × x² = x³

∴ x³(5x² + 4x + 1)

∵ x³ × 5x² = 5x^5

∵ x³ × 4x = 4x^4

∵ x³ × 1 = x³

∴ The volume = $5x^{5}+4x^{4}+x^{3}$

5 0

3 years ago

What is the product of any nonzero real number and it’s multiplicative inverse?

Elis [28]

Answer:

Step-by-step explanation:

The product of any nonzero real number and its multiplicative inverse (reciprocal) is always 1. This is called the multiplicative identity or the identity element of multiplication.

~Hope this helps!~

7 0

4 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

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brainly.com/question/18591940

8 0

2 years ago

4a - 7 = 5 What is the answer 2 step equation

Alex777 [14]

Answer:

A= 3

Step-by-step explanation:

4a - 7 = 5

move the constant to the right

4a= 5+7

divide

4a=12

Awnser:

A= 3

3 0

3 years ago

Erica collected a total of $180 for her favorite charity over the first 3 months of the year. She collected the same amount in t

ankoles [38]

X+x+3x= 180
5x= 180
x= 36

3(36)= 108
Your answer is D. $108

4 0

3 years ago

Read 2 more answers