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goldenfox [79]
2 years ago
15

PLEASE HELP DUE RIGHT NOW!!!

Mathematics
1 answer:
Anika [276]2 years ago
7 0

Answer:

linear

Step-by-step explanation:

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A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?
Pachacha [2.7K]
Answer is B
area for a trapezoid is [( Base 1 + Base 2 ) * height] /2
which in this case would be [( 7 + 10 ) * 7]/2
(17)7/2
59.5
4 0
2 years ago
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Find the point(s) on the ellipse x = 3 cost, y = sin t, 0 less than or equal to t less than or equal to 2pi closest to the point
Lady_Fox [76]

Answer and Step-by-step explanation:

The computation of points on the ellipse is shown below:-

Distance between any point on the ellipse

(3 cos t, sin t) and (\frac{4}{3},0) is\\\\ d = \sqrt{(3 cos\ t - \frac{4}{3}^2) } + (sin\ t - 0)^2\\\\ d^2 = (3 cos\ t - \frac{4}{3})^2 + sin^2 t

To minimize

d^2, set\ f' (t) = 0\\\\2(3cos\ t - \frac{x=4}{3} ).3(-sin\ t) + 2sin\ t\ cos\ t = 0\\\\ 8 sin\ t - 16 sin\ t\ cos\ t = 0\\\\ 8 sin\ t (1 - 2 cos\ t) = 0\\\\ sin\ t = 0, cos\ t = \frac{1}{2} \\\\ t= 0, \ 0, \pi,2\pi,\frac{\pi}{3} , \frac{5\pi}{3}

Now we create a table by applying the critical points which are shown below:

t            d^{2} = (3\ cos t - \frac{4}{3})^{2} + sin^{2}t

0           \frac{25}{9}<u />

<u />\pi           \frac{169}{9}

2\pi         \frac{25}{9}

\frac{\pi}{3}          \frac{7}{9}

\frac{5\pi}{3}         \frac{7}{9}

When t = \frac{\pi}{3}, x is \frac{3}{2} and y is \frac{\sqrt{3} }{2}. So, the required points are (\frac{3}{2},\frac{\sqrt{3} }{2})

When t = \frac{5\pi}{3}, x is \frac{3}{2} and y is \frac{-\sqrt{3} }{2}. So, the required points are (\frac{3}{2},\frac{-\sqrt{3} }{2})

5 0
3 years ago
A line has a slope of - 1/4 and passes through point(-5/4,1)<br> What is the equation of the line?
Levart [38]

Answer:

y= -1/4x - 1/4

Step-by-step explanation:

y - y1 = m(x - x1)

y - 1 = -1/4 (x -(-5/4))

y - 1 = -1/4x - 5/4

y = -1/4x - 1/4

6 0
3 years ago
The bottom of sigma is n=1
alekssr [168]
Answers:
The series converges
The sum is -8/3

-----------------------------------------------------

a = -4 is the first term
r = -1/2 is the common ratio
the reason why is because the expression -4(-1/2)^(n-1) is in the form a(r)^(n-1). Notice how -4 matches with the 'a'; the -1/2 matches with the r

The common ratio will determine if the infinite series converges or not. 
r = -1/2 leads to |r| = |-1/2| = 1/2 = 0.5
Since |r| < 1 (in this case 0.5 < 1) is true, this means the series does converge.
Put another way, because r = -1/2 = -0.5 makes -1 < r < 1 true, the series converges.

Use the formula below to find the converging value S
S = a/(1-r)
S = -4/(1-(-1/2))
S = -4/(1+1/2)
S = -4/(2/2+1/2)
S = -4/(3/2)
S = (-4/1)/(3/2)
S = (-4/1)*(2/3)
S = (-4*2)/(1*3)
S = -8/3
The infinite series converges to -8/3
So the sum is -8/3

5 0
3 years ago
Y =-0.011x + 40.604<br> What is the slope
svp [43]
0.11×11%×40.60%×4=0.11×+40%.604
5 0
3 years ago
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