To solve this problem we will begin by applying the given relations of density in terms of mass and volume, and from this last value we will take its geometric measurement for a sphere (Approximation of a planet) From there we will find the radius of the planet. Finally we will make a comparison between the radius of the new planet and the radius of the earth to understand its proportion.
Defining the Volume variables we have to
Here
V= Volume
m = mass
=Density
For a spherical object the Volume is
PART A)
Equation we have
In this case the mass of new planet is 5.5times the mass of Earth,
Then,
The mass of the Earth is kg and the density is ,
Replacing we have that,
Therefore the radius of this new planet is
PART B) The value of radius of the Earth is
Then the relation between them is
Therefore the radius of the new planet in terms of radius of the Earth is
Answer:
C. 0.50 m
Hope this helps,
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Answer:
<u>Box 1</u>
Explanation:
Formula we are using :
<u>Force = mass × acceleration</u>
or
<u>mass = Force / acceleration</u> (since mass needs to be found)
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Box 1 :
⇒ mass = 5 N / 5 m/s²
⇒ mass = 1 kg
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Box 2 :
⇒ mass = 5 N / 0.75 m/s²
⇒ mass = 5 × 4/3 = 20/3 kg
⇒ mass = 6.67 kg
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Box 3 :
⇒ mass = 5 N / 4.3 m/s²
⇒ mass = 50/43 kg
⇒ mass = 1.16 kg
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On comparing Box 1, Box 2, and Box 3, we understand that <u>Box 1</u> has the smallest mass
Answer:
Electrons have an electric charge of −1, which is equal but opposite to the charge of a proton, which is +1
Explanation:
Answer:
I would have to say B THe su would rise in the west and set in the east But this is just a guess