Answer:
Rain jackets are coated in durable water-repellant (DWR) finish, a hydrophobic glaze that allows the coats to be breathable, yet waterproof. It lets water vapor—like sweat—out, but keeps rain from getting in. ... Without a DWR, the raincoat is just a coat. So, you'll need to recoat it.
Explanation:
This is according to the web
Reflection, i<span>t is the phenomena of getting back the light you've shown from a light source with the same angle. r</span>efraction, <span>It is the phenomena of bending of light when it changes it medium. This </span>can<span> rarer to denser or denser to rarer. d</span>iffraction,<span> It is the phenomena of bending of light near the edges of the object. hope this helps
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The answer would be Gravity.
Gravity is pulling the weight down, which is pulling the car up the ramp.
Answer:
a. v₁ = 16.2 m/s
b. μ = 0.251
Explanation:
Given:
θ = 15 ° , r = 100 m , v₂ = 15.0 km / h
a.
To determine v₁ to take a 100 m radius curve banked at 15 °
tan θ = v₁² / r * g
v₁ = √ r * g * tan θ
v₁ = √ 100 m * 9.8 m/s² * tan 15° = 16.2 m/s
b.
To determine μ friction needed for a frightened
v₂ = 15.0 km / h * 1000 m / 1 km * 1h / 60 minute * 1 minute / 60 seg
v₂ = 4.2 m/s
fk = μ * m * g
a₁ = v₁² / r = 16.2 ² / 100 m = 2.63 m/s²
a₂ = v₂² / r = 4.2 ² / 100 m = 0.18 m/s²
F₁ = m * a₁ , F₂ = m * a₂
fk = F₁ - F₂ ⇒ μ * m * g = m * ( a₁ - a₂)
μ * g = a₁ - a₂ ⇒ μ = a₁ - a₂ / g
μ = [ 2.63 m/s² - 0.18 m/s² ] / (9.8 m/s²)
μ = 0.251
