alguien que me pase sus tareas de fisica de 18 de septiembre es de aprende en casa pleaseee doy de coronita y todo

A particle (mass = 2.0 mg, charge = −6.0 μC) moves in the positive direction along the x axis with a velocity of 3.0 km/s. It en

Virty [35]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The acceleration would be $a = 0.003* 6 =0.018\ m/s^2$

Explanation:

The objective of this solution is to obtain the acceleration of the particle

Now looking at Newton law which is mathematically represented as

$F = ma$

Where F is the force experience by a particle

m is the mass of the particle

a is the acceleration of the particle

And also this force is equivalent to magnetic force in a magnetic field which is mathematically represented as

$F = qvB$

Where q is the charge of the particle

v is the velocity of the charge

B is the magnetic field the charge is under it influence

Now equating this two formulas

$ma = qvB$

Making a the subject we have

$a = \frac{qvB}{m}$

In the question the direction of the is in the positive x-axis which is $i$ hence the direction would be in the $i$ direction

So substituting $(2.0i +3.0j+4.0k)mT = (2.0i +3.0j+4.0k)*10^{-3}T$ for B

$a = \frac{q}{m} * v (2.0i +3.0j +4.0k)*10^{-3}$

Substituting $3.0 Km /s = 3.0*10^{3}\ m/s$ for v and $-6.0 \muC = -6.0*10^{-6} C$ for q

$a = \frac{-6.0*10^{-6}}{2.0*10^{-3}} * 3.0*10^{3} *(2i+3j+4k) *10^{-3}$

$a = 0.003 * 3i(2i+3j+4k)$

$a = 0.003 *((3*2)i \ \cdot i \ +(3*3) i \ \cdot \ j \ + (3*4)i \ \cdot \ k)$

According to vector multiplication

$i \cdot i = j \cdot j = k\cdot k = 1\\\\and \ i\cdot j = i\cdot k = 0$

So

$a = 0.003* 6 =0.018\ m/s^2$

8 0

3 years ago

Hello, can you please help me with this problem?

dolphi86 [110]

Answer:

You're right already. It's B)

5 0

3 years ago

Read 2 more answers

3. No simple machine is ideal in practice.<br>Why

Kobotan [32]

Answer:

beacuase

Explanation:

4 0

3 years ago

6. Is inertia the reason for moving objects maintaining motion or the name given to this property?

marshall27 [118]

Inertia is the name. Inertia is when a moving object stays in motion unless stopped by an outside force. This is Newton’s first law of motion

8 0

3 years ago

A bead slides without friction around a loop the-loop. The bead is released from a height of 17.6 m from the bottom of the loop-

solong [7]

Answer:

N₁ = 393.96 N and N = 197.96 N

Explanation:

In This exercise we must use Newton's second law to find the normal force. Let's use two points the lowest and the highest of the loop

Lowest point, we write Newton's second law n for the y-axis

N -W = m a

where the acceleration is ccentripeta

a = v² / r

N = W + m v² / r

N = mg + mv² / r

we can use energy to find the speed at the bottom of the circle

starting point. Highest point where the ball is released

Em₀ = U = m g h

lowest point. Stop curl down

$Em_{f}$ = K = ½ m v²

Emo = Em_{f}

m g h = ½ m v²

v² = 2 gh

we substitute

N = m (g + 2gh / r)

N = mg (1 + 2h / r)

let's calculate

N₁ = 5 9.8 (1 + 2 17.6 / 5)

N₁ = 393.96 N

headed up

we repeat the calculation in the longest part of the loop

-N -W = - m v₂² / r

N = m v₂² / r - W

N = m (v₂²/r - g)

we seek speed with the conservation of energy

Em₀ = U = m g h

final point. Top of circle with height 2r

$Em_{f}$ = K + U = ½ m v₂² + mg (2r)

Em₀ = Em_{f}

mgh = ½ m v₂² + 2mgr

v₂² = 2 g (h-2r)

we substitute

N = m (2g (h-2r) / r - g)

N = mg (2 (h-r) / r 1) = mg (2h/r -2 -1)

N = mg (2h/r - 3)

N = 5 9.8 (2 17.6 / 5 -3)

N = 197.96 N

Directed down

3 0

3 years ago