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A girl drops a stone from the top a tower 45m tall. At the same time, a boy standing at the base of the tower, projects another

Advocard [28]

Answer:

(i) The stones meet at 1.8 second

(ii) The point at which the stones meet, is 28.8 m above the base of the building and 16.2 m below the top of the building.

Explanation:

(i)

First we consider the stone dropped by the girl. We have data:

Vi = Initial Velocity of Stone = 0 m/s (Since the stone was initially at rest)

t = Time Period

g = 10 m/s²

s₁ = Distance Covered by Stone

Using 2nd equation of motion, we get:

s₁ = Vi t + (0.5)gt²

s₁ = (0)(t) + (0.5)(10)t²

s₁ = 5t² ----- equation (1)

Now, we consider the stone throne vertically upward by the boy. We have data:

Vi = Initial Velocity of Stone = 25 m/s

t = Time Period

g = - 10 m/s² (negative sign due to upward motion)

s₂ = Distance Covered by Stone

Using 2nd equation of motion, we get:

s₂ = Vi t + (0.5)gt²

s₂ = (25)(t) + (0.5)(-10)t²

s₂ = 25t - 5t² ----- equation (2)

At, the point where both the stones meet, the sum of distances covered by both stones must be equal to the height of building (i.e 45 m).

s₁ + s₂ = 45

using values from equation (1) and equation (2)

5t² + 25t - 5t² = 45

25t = 45

t = 45/25

t = 1.8 sec

(ii)

using this value of of t in equation (2)

s₂ = (25)(1.8) - (5)(1.8)²

s₂ = 28.8 m

using this value of of t in equation (1)

s₁ = (5)(1.8)²

s₁ = 16.2 m

Hence, the point at which the stones meet, is 28.8 m above the base of the building and 16.2 m below the top of the building.

6 0

3 years ago

The study of the interaction of electrical and magnetic fields, and their interaction with matter, is called _____.

Dafna11 [192]

It is called Electromagnetism

8 0

3 years ago

A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate moving at a steady speed, Paige pushes back

VMariaS [17]

Answer:

Hence, work done= 287.54 J

Explanation:

Given data:

angle of ramp with the ground θ =20°

force applied = 76 N

work done on the crate to slide down 4 m down the ramp

W= F×d cosθ ( only the cos component of the force will slide the crate down)

W= 76×4×cos20= 287.54 J

4 0

3 years ago

In some areas where there are adequate geothermal resources, a pollutant occurs naturally that escapes, making the location unsu

Luba_88 [7]

Hydrogen sulfide gas

7 0

2 years ago

Read 2 more answers

1) A piano tuner is testing a wire currently under 2000 N tension. The wire is 1.5 m long and has a mass of 20 g. If the tuner's

m_a_m_a [10]

1.

Answer:

N = 77

Explanation:

1) As we know that Tension in the wire is given as

T = 2000 N

now mass per unit length of the wire is given as

$\frac{m}{L} = \frac{20 \times 10^{-3} kg}{1.5 m}$

$\frac{m}{L} = 0.013 kg/m$

Now fundamental frequency is given as

$f_o = \frac{1}{2L}\sqrt{\frac{T}{m/L}}$

$f_o = \frac{1}{2\times 1.5}\sqrt{\frac{2000}{0.013}}$

$f_o = 129 Hz$

now highest frequency is given as 10000 Hz

so total harmonics is given as

$N = \frac{10000}{129}$

$N = 77$

2.

Answer:

D) 7.14 Hz

Explanation:

As we know that

speed = (frequency)(wavelength)

given that

speed = 400 m/s

wavelength = 28 m

so frequency is given as

$f = \frac{400}{28}$

$f = 14.3 Hz$

now if wavelength is doubled then we will have

$wavelength = 56 m$

new frequency will be

$f = \frac{400}{56}$

$f = 7.14 hz$

3.

Answer:

Number of nodes = 4

A) 4

Explanation:

Number of nodes = number of harmonics + 1

so here we know that

number of harmonics = 3

Number of nodes = 3 + 1

Number of nodes = 4

4.

Answer:

C) 35.1 Hz

Explanation:

fundamental frequency in an organ pipe closed at one end is given as

$f = \frac{v}{4L}$

here we know that

v = 345 m/s

L = 2.46 m

now we have

$f = \frac{345}{4(2.46)}$

$f = 35.1 Hz$

5.

Answer:

A) 570

Explanation:

Number of harmonics is given as

$N = \frac{maximum :\frequency}{fundamental\: frequency}$

$N = \frac{20,000}{35.1}$

$N = 570$

6.

Answer:

$v = 37.12 m/s$

Explanation:

For fundamental frequency we know that

$f_o = \frac{v}{2L}$

here we know that

$f_o = 58 Hz$

$L = 32 cm$

now we have

$58 = \frac{v}{2(0.32)}$

$v = 37.12 m/s$

7 0

3 years ago