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ra1l [238]
3 years ago
5

3. Two balls are rolling toward each other. One has a momentum of 85kg*m/s, and the other has a momentum of -85kg*m/s. What will

be the total momentum of the system after they collide? In what direction will they move after they collide if it is an inelastic collision? Answer:​
Physics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

The total momentum is zero.

Explanation:

This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.

In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.

(P_{1})-(P_{2})=P_{3}

where:

P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]

P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]

P₃ = Final momentum after the collision [kg*m/s]

(85) - 85 = P_{3}\\P_{3}= 0

There is no movement of any of the balls, they remain at rest after the impact.

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A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
and so, the average velocity is
v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
Contrast the force of gravity between these pairs of objects a 1 kg mass and a 2 kg mass that are 1 m apart and two 2 kg masses
Yuki888 [10]

Solution

Force between pair of objects of masses 1kg and 2kg that are 1m apart is given as

F=G\times \frac{1\times 2}{1^2}

here G is gravitational constant

G=6.674\times10^{-11}Nm^2kg^{-2}

therefore,

F=6.674\times10^{-11}Nm^2kg^{-2}\times 2

F=13.348\times10^{-11}Nm^2kg^{-2}

similarly Force between pair of objects of masses 2kg each that are 1m apart is given as

F'=G\times \frac{2\times 2}{1^2}

F'=6.674\times10^{-11}Nm^2kg^{-2}\times 4

F'=2\times 13.348\times10^{-11}Nm^2kg^{-2}

or F'=2F

it means  Force between pair of objects of masses 2kg each that are 1m apart is equal to twice the Force between pair of objects of masses 1kg and 2kg that are 1m

7 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH MY PHYSICS QUESTIONS? I NEED CORRECT ANSWERS ONLY!
BARSIC [14]
<h2>Right answer: acceleration due to gravity is always the same </h2><h2 />

According to the experiments done and currently verified, in vacuum (this means there is not air or any fluid), all objects in free fall experience the same acceleration, which is <u>the acceleration of gravity</u>.  

Now, in this case we are on Earth, so the gravity value is 9.8\frac{m}{s^{2}}  

Note the objects experience the acceleration of gravity regardless of their mass.

Nevertheless, on Earth we have air, hence <u>air resistance</u>, so the afirmation <em>"Free fall is a situation in which the only force acting upon an object is gravity" </em>is not completely  true on Earth, unless the following condition is fulfiled:

If the air resistance is <u>too small</u> that we can approximate it to <u>zero</u> in the calculations, then in free fall the objects will accelerate downwards at 9.8\frac{m}{s^{2}} and hit the ground at approximately the same time.  


5 0
4 years ago
In 1600, Dr. William Gilbert coined the term “electrica,” a word that gave rise to our word electricity.
mrs_skeptik [129]

They recorded the first references to electrical effects, such as static electricity and lightning, over 2,500 years ago. It was not until 1600 that a man named Dr. William Gilbert coined the term “electrica,” a Latin word which describes the static charge that develops when certain materials are rubbed against amber.

3 0
3 years ago
in vision, the ____ stream controls identification of an object, and the ____ stream controls action toward the object.
prisoha [69]

Answer: In vision, the ventral stream controls identification of an object, and the dorsal stream controls action toward the object.

Explanation: The ventral stream is associated with object recognition and form representation.

Dorsal stream  a pathway that carries visual information from the primary visual cortex to the parietal lobe.

Hope it helps :)

7 0
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