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ra1l [238]
3 years ago
5

3. Two balls are rolling toward each other. One has a momentum of 85kg*m/s, and the other has a momentum of -85kg*m/s. What will

be the total momentum of the system after they collide? In what direction will they move after they collide if it is an inelastic collision? Answer:​
Physics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

The total momentum is zero.

Explanation:

This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.

In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.

(P_{1})-(P_{2})=P_{3}

where:

P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]

P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]

P₃ = Final momentum after the collision [kg*m/s]

(85) - 85 = P_{3}\\P_{3}= 0

There is no movement of any of the balls, they remain at rest after the impact.

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Comparing infrared and ultraviolet, we can say that __________. Comparing infrared and ultraviolet, we can say that __________.
Fudgin [204]

Answer: Comparing infrared and ultraviolet, ''we can say that infrared has longer wavelength and lower photon energy''

8 0
3 years ago
Your answer is CORRECT. Let v⃗ be the vector with initial point (8,1) and terminal point (6,4). Express v⃗ as a linear combinati
Phoenix [80]

Answer:

1) Option E is correct.

vector v = (-2î + 3ĵ)

2) Option C is correct.

The vertical component of vector v = 2

3) Option B is correct.

The vector sum of u and v = (4î - 9ĵ)

4) Option B is correct.

5u - 4v = (-30î - -23ĵ)

5) Option F is correct.

Magnitude of v = √32 units = 4√2 units = 5.66 units

6) Option F is correct.

Unit vector in the same direction as v is

v = (î + 3ĵ)/√10 = [(1/√10), (3/√10)]

Explanation:

1) vector v has initial point (8,1) and terminal point (6,4)

Write vector v as a linear combination of the standard unit vector.

v represented in standard form is given as

Vector v = (final position vector) - (initial position vector) = (6î + 4ĵ) - (8î + ĵ) = (-2î + 3ĵ)

2) v be the vector with initial point (−5,1) and terminal point (5,3). Find the vertical component of this vector.

v represented in standard form is given as

Vector v = (final position vector) - (initial position vector) = (5î + 3ĵ) - (-5î + ĵ)

v = (10î + 2ĵ)

The vertical component is the ĵ-component and it is equal to 2

3) Find the sum of the vectors u =6i −4j and v⃗ =−2i −5j

Vector sum is done on a per component basis

Sum = u + v = (6î - 4ĵ) + (-2î - 5ĵ) = (4î - 9ĵ)

4) Given vectors u⃗ =⟨−2,−3⟩ and v⃗ =⟨5,2⟩; find 5u⃗ −4v⃗

u = (-2î - 3ĵ)

v = (5î + 2ĵ)

5u - 4v = 5(-2î - 3ĵ) - 4(5î + 2ĵ)

= (-10î - 15ĵ) - (20î + 8ĵ)

= (-30î - 23ĵ)

5) Find the magnitude of the vector v = (4i−4j)

Magnitude of a vector is given as

/v/ = √[vₓ² + vᵧ²]

where vₓ and vᵧ are x and y components of the velocity.

/v/ = √[(4²) + (-4)²] = 4√2 units = 5.66 units

6) Given the vector v =⟨1,3⟩; find a unit vector in the same direction as v

Unit vector in the direction of a vector = (vector)/(magnitude of vector)

Vector v = (î + 3ĵ)

Magnitude of vector v = √[1² + 3²] = √10

Unit vector in the same direction as v = (î + 3ĵ)/√10

Hope this Helps!!!

8 0
3 years ago
A balloon contains 0.04m3 of air at a pressure of 1.20 x 105Pa. Calculate the pressure required to reduce its volume to 0.025m3
sdas [7]

Answer:

you can simply answer p1v1=p2v2 p2 = p1v1÷ p2 then inter what given in the formula you get it pl=1.20x 105pa vl= 0.40m3 v2=0.025m3

4 0
3 years ago
Light of wavelength 630 nm falls on two slits and produces an interference pattern in which the third-order bright red fringe is
goblinko [34]

Answer:

d \frac{x}{l} = m×  λ⇒ d = λ ×m×l / x

= 630×10^{-9} m × 3×3m/ 45×10^{-3} m

= 1.26×10^{-4}m

Explanation:

the above calculation is based on Young’s double slit experiment where the two slits provide two coherent light sources which results either constructive interference or destructive interference when passing through a double slit.

6 0
3 years ago
When you apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed ().When you apply a f
elena-s [515]

Answer:

Explanation:

When we apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed. So net force on the block is zero .

It implies that a force ( frictional ) acts on it which is equal to 76 N in opposite direction ( friction )

When we apply  a greater force on it it starts moving with acceleration .

This time kinetic friction acts on it due to rough ground equal to 76 N .This is limiting friction ( maximum friction )

Net force on the body in later case

= 89 - 76

= 13 N

Force by ground on the block in horizontal direction = 76 N ( FRICTIONAL FORCE )

=

3 0
4 years ago
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