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Tom [10]
3 years ago
5

How do you design a good scientific experiment?

Chemistry
1 answer:
kirill [66]3 years ago
7 0

Answer:

To design a good scientific research, there is a few things you need. You need to have an experiment first of course . You need an hypothesis, a conclusion, and research. Question,analysis, and observation.

Explanation:

If this helps : In fifth grade we did a scientific experiment that we had to present. I chose to do if bananas turned bad first under UV light or sun rays and my hypothesis was that they would turn bad under the sun-rays. My conclusion was that they didn't. My observation was written down in a notebook of what I saw with each passing day. Research was what I looked up about of course how long bananas lasted and how long they didn't.

Hope it helps :)

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A student creates a solution by dissolving some Na2SO4 (molar mass = 142.05 g/mol) in enough water to create 0.500 L of solution
NeX [460]

Answer : The mass of Na_2SO_4 is, 4.43 grams.

Explanation :

As we know that, when Na_2SO_4 dissolve in water then it dissociates to give 2 mole of sodium ion Na^+ and 1 mole of sulfate ion SO_4^{2-}

The chemical reaction will be:

Na_2SO_4\rightarrow 2Na^++SO_4^{2-}

Thus, the concentration of Na_2SO_4 = \frac{\text{Concentration of }Na^+}{2}=\frac{0.125M}{2}=0.0625M

First we have to calculate the moles of Na_2SO_4

\text{Concentration of }Na_2SO_4=\frac{\text{Moles of }Na_2SO_4}{\text{Volume of solution}}

0.0625M=\frac{\text{Moles of }Na_2SO_4}{0.500L}

\text{Moles of }Na_2SO_4=0.0312mol

Now we have to calculate the mass of Na_2SO_4

\text{Mass of }Na_2SO_4=\text{Moles of }Na_2SO_4\times \text{Molar mass of }Na_2SO_4

Molar mass of Na_2SO_4 = 142 g/mol

\text{Mass of }Na_2SO_4=0.0312mol\times 142g/mol=4.43g

Thus, the mass of Na_2SO_4 is, 4.43 grams.

6 0
3 years ago
Which of the following did Malthus fail to take into consideration?
saveliy_v [14]

Answer: humans would find more efficient ways of growing crops

Explanation:

4 0
3 years ago
Read 2 more answers
Gastric juice (pH 1.5) is produced by pumping HCl from blood plasma (pH 7.4) into the stomach. Calculate the amount of free ener
Annette [7]

Given question is incomplete. The complete question is as follows.

Gastric juice (pH 1.5) is produced by pumping HCl from blood plasma (pH 7.4) into the stomach. Calculate the amount of free energy required to concentrate the H in 1 liter of gastric juice at 37 degree of centigrade. Under cellular conditions, how many moles of ATP must be hydrolyzed to provide this amount of free energy? the free energy change for ATP hydrolysis under cellular conditions is about -58 kJ/mol. Ignore the effects of the transmembrane electrical potential.

Explanation:

The given data is as follows.

       Gastric juice pH = 1.5,        blood plasma pH = 7.4

    Temperature = 37^{o}C = (37 + 273) K

                           = 310 K

Now, relation between pH and concentration of hydrogen ions is as follows.

           pH = -log [H^{+}]

At pH = 1.5, we will calculate the [H^{+}] as follows.

            [H^{+}] = 10^{-pH}

                        = 10^{-1.5}

                        = 3.16 \times 10^{-2} M  (C_{2})

At pH = 7.4, we will calculate the [H^{+}] as follows.

            [H^{+}] = 10^{-pH}

                        = 10^{-7.4}

                        = 3.98 \times 10^{-8} M   (C_{1})

Also,

        \Delta G_{f} = RT ln (\frac{C_{2}}{C_{1}})

                      = 8.314 \times 310 \times ln (\frac{3.16 \times 10^{-2}}{3.98 \times 10^{-8}})

                      = 35 kJ/mol

So, the amount of ATP necessary to provide 35 kJ is as follows.

           \frac{35 kJ}{58 kJ/mol}

             = 0.6 mol

Therefore, we can conclude that 0.6 moles of ATP must be hydrolyzed to provide this amount of free energy.

7 0
3 years ago
Which of the following is an example of velocity?
Musya8 [376]
I believe the answer is B.
3 0
4 years ago
Read 2 more answers
Find energy is the wavelength is 5.2x10^-7m (Show work)
RoseWind [281]

Answer:

E = 3.825×10⁻¹⁹ J

Explanation:

Wavelength of photon = 5.2 ×10⁻⁷m

Energy of photon = ?

Solution:

Formula:

E = hc/λ

h = plancks constant = 6.63×10⁻³⁴ Js

c = speed of wave = 3×10⁸ m/s

by putting values,

E = 6.63×10⁻³⁴ Js ×3×10⁸ m/s / 5.2 ×10⁻⁷m

E = 19.89×10⁻²⁶ J.m / 5.2 ×10⁻⁷m

E = 3.825×10⁻¹⁹ J

4 0
3 years ago
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