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Elis [28]
3 years ago
11

The equilibrium for the indicator methyl orange is HC14H14SO3(red) + H2O C14H14SO3−(yellow) + H3O+ The reaction is exothermic.

Chemistry
1 answer:
muminat3 years ago
4 0

Answer:

The solution will turn red.  

Explanation:

HC₁₄H₁₄SO₃ + H₂O ⇌ HC₁₄H₁₄SO₃⁻ +H₃O⁺

     (red)                           (yellow)

Methyl orange is a weak acid in which the ionized and unionized forms are distinct colours and are in equilibrium with each other,

At about pH 3.4,  the two the forms are present in equal amounts, and the indicator colour is orange.

If you add more acid, you are disturbing the equilibrium.

According to Le Châtelier's Principle, when you apply a stress to a system at equilibrium, it will respond in such a way as to relieve the stress.

The system will try to get rid of the added acid, so the position of equilibrium will move to the left.

More of the unionized molecules will form, so the solution will turn red.

 

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hich statement is true? A. An acid with a large pKa will be a better conductor of electricity than one with a smaller pKa. B. An
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Answer:

\boxed{\text{B is correct}}

Explanation:

Kₐ and pKₐ are measures of the strength of an acid. For example,

HX + H₂O ⇌ H₃O⁺ + X⁻;  Kₐ = 10¹⁰,  pKₐ = -10

HA + H₂O ⇌ H₃O⁺ + A⁻; Kₐ = 10⁻¹⁰, pKₐ =  10

HX is a strong acid, because it has a larger Kₐ, that is, the position of equilibrium lies far to the right.

However, pKₐ is the negative logarithm of Kₐ, so HX has the smaller pKₐ.

Similarly, Ha is a weak acid, but it has the larger pKₐ.

Strong acid: Large Kₐ ⇔ Low pKₐ

Weak acid:   Small Kₐ ⇔ High pKₐ

A is wrong. HA is a weak acid, so it produces only a few hydronium ions.

B is correct. The rate of corrosion depends on the concentration of hydronium ions. HA is a weak acid, so it is less corrosive than an acid with a small pKₐ.

C is wrong. HX is a strong acid, so there are more ions to carry the current. HX will be a good conductor of electricity.

D is wrong. HX is a strong acid, so it provides more hydronium ions and is more corrosive.

E is wrong. HX is a strong acid, so it provides more hydronium ions to stimulate the taste buds.

\boxed{\textbf{B is correct}}

7 0
4 years ago
When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coeffici
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The values of the coefficients would be 4, 5, 4, and 6 respectively.

<h3>Balancing chemical equations</h3>

The equation of the reaction can be represented by the following chemical equation:

ammonia (g) + oxygen (g) ---> nitrogen monoxide (g) + water (g)

  4NH_3(g)     +    5O_2(g)        --->           4NO(g)              +  6H_2O(g)

Thus, the coefficient of ammonia will be 4, that of oxygen will be 5, that of nitrogen monoxide will be 4, and that of water will be 6.

More on balancing chemical equations can be found here: brainly.com/question/15052184

#SPJ1

5 0
2 years ago
Can anyone pls summarize this for me
kotykmax [81]

Answer:here is the answer

Scholarcy, the online article summarizer tool, reads your research articles, reports and book chapters in seconds and breaks them down into bite-sized sections – so you can quickly assess how important any document is to your work.

Explanation:

8 0
3 years ago
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Batteries involve the flow of electricity from one metal to another. What happens to these metals to cause the batteries to, eve
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4 0
3 years ago
At 46°C a sample of ammonia gas exerts a pressure of 5.3 atm. What is the pressure when the volume of the gas is reduced to one-
snow_lady [41]

Hello there!

As you may know, pressure and volume have an inverse relationship. This means that as pressure increases, volume decreases (and as volume increases, pressure decreases).

In this problem, the volume of the gas is reduced to 0.250 its original value. This means that the pressure should be higher than it was originally.

We can use Boyle's Law to solve this problem, seeing that temperature is kept constant.

P1V1 = P2V2

Let's rearrange this equation to isolate the variable we need, P2.

P1V1

-------   = P2

 V2

That's better! Now that we have that down, let's plug in the numbers we were given.

(5.3atm) * (V1)

-------------------- = P2

0.25(V1)

We can get rid of V1, as the number would be equal to 1 (anything divided by itself is equal to 1).

5.3atm

---------- = 21.2 atm

0.25L

Now, while the number is significantly higher, this is quite reasonable.

Let's plug it in and see if we get what we should:

5.3(V1) = (0.25V1)(21.2)

--------

0.25V1

21.2 atm = 21.2 atm

Seems right to me!

Feel free to comment if you need any more help. :)

5 0
4 years ago
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