What type of chemical reaction is CaCaI2 + F2 = CaF2 + CI2

How to balance lead and silver acetate yields lead (||) acetate and silver

arsen [322]

The given elements put into an equation using their symbols are as follows:
Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + 2Ag

That is your final equation

The coefficients are 2 + 2 = 1 + 2

3 0

3 years ago

Classify unopened root beer as an element, a compound, a homogeneous mixture, or a heterogeneous mixture

maxonik [38]

The different state of material based on its ingredients are-

1. Compound: The compound is in which there are more than one molecule in which chemical bond is there.

2. Mixture: It is basically presence of two or more compounds in which there is no chemical bonds.

The mixture may be of two types (i) homogeneous and (ii) Heterogeneous. In the homogeneous mixture there is uniformity of the mixed compound (like air in water) and some chemical process is needed to separate the compounds. Whereas heterogeneous mixtures (like chalk in water) are easily separable by any physical process.

In the root beer which is a soft drink which is obtained in different flavor sometime with caffeine and without caffeine. The unopened bottle of root beer is homogeneous mixture.

4 0

3 years ago

What is the chemical formula for the ionic compound calcium chloride?

gulaghasi [49]

C a C l ^2

Hope this helps

7 0

3 years ago

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A chemist heats the block of copper as shown in the interactive, then places the metal sample in a cup of oil at 25.00 °C instea

Mazyrski [523]

When the oil is added to the heated copper, the energy in the system is

conserved.

The mass of the oil in the cup, is approximately 64.73 grams.

Reasons:

The question parameters are;

Temperature of the oil in the cup = 25.00°C

Final temperature of the oil and copper, T₂ = 27.33 °C

Specific heat of copper, c₂ = 0.387 J/(g·°C)

Specific heat capacity of oil, c₁ = 1.74 J/(g·°C)

Required:

The mass of oil in the cup.

Solution:

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating, T₂ = 65.17°C

Temperature of the copper after being placed in the cup of oil, T₂ = 27.33°C

Heat lost by copper = Heat gained by the oil

m₂·c₂·(T₂ - T₃) = m₁·c₁·(T₃ - T₁)

Therefore, we get;

17.920 × 0.387 × (65.17 - 27.33) = m₁ × 1.74 × (27.33 - 25)

262.4219136 = 4.0542·m₁

m₁ ≈ 64.73

The mass of the oil in the cup, m₁ ≈ 64.73 g

Learn more here:

brainly.com/question/21406849

Possible part of the question obtained from a similar question online, are;

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating = 65.17°C

6 0

3 years ago

A train took 18 hours to finish a 1530 miles journey. What was

Greeley [361]

Answer: 85Mph
Explanation: 1530 divided by 18=85

3 0

4 years ago