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vfiekz [6]
3 years ago
12

Water is a pure substance. Which of the following is true about water?

Chemistry
1 answer:
Nastasia [14]3 years ago
8 0

Answer:

A chemical change is required to separate the elements present in it.

Explanation:

The only true statement from the choices given is that water as a pure substance requires a chemical change to separate the elements present in it.

Water is a molecule consist of two atoms of hydrogen and one atom of oxygen.

  • The atoms are covalently bonded together.
  • A chemical process, the electrolysis of water is often used to separate the atoms of a water.
  • Physical changes cannot be used to separate the atoms of water.
  • Water is a compound which consists of two elements.

Therefore, we see that only the first choice satisfies this problem.

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Find the quantinum numbers n,m,l,s for the last of potassium layer pleasee help explain correctly all
Fantom [35]

Answer:

Quantum numbers of the outermost electron in potassium:

  • n = 4.
  • l  = 1.
  • m_l = 0.
  • Either m_s = 1/2.

Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the 4s orbital (fourth s orbital.)

The quantum number n (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, n = 4 for this electron.

The quantum number l (the angular momentum quantum number) specifies the shape (s, p, d, etc.) of an electron. l = 1 for s\! orbitals (such as the one that contains this electron.

Quantum numbers n and l specify the shape of an orbital. On the other hand, the magnetic quantum number m_l specifies the orientation of these orbitals in space.

However, s orbitals are spherical. Regardless of the value of n, the only possible m_l value for electrons in s\! orbitals is m_l = 0.

The spin quantum number m_s distinguishes between the two electrons in an orbital. The two possible values of m_s \! are (+1/2) and (-1/2). Typically, the first electron in an orbital is assigned an upward (\uparrow) spin, which corresponds to m_s = (+1/2).

5 0
3 years ago
If a person is throwing darts at a target, and shoots three in a row in the same spot on the 20 section outer ring, but none in
Gennadij [26K]
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Please give me a clear message on what to do.<br> how do you change your brainly username?
emmainna [20.7K]

Answer:

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How many protons are in the nucleus of an atom with an atomic number of 15
vodomira [7]

Answer:

In the given case, the atomic number of the given atom is 15, hence its nucleus contains 15 protons. The number of protons and electrons are the same in atom and that is what keeps it neutral. In the second case, the atomic number is 20. Hence, the atom will contain a total of 20 protons in its nucleus.

Explanation:

4 0
2 years ago
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When balancing redox reactions under basic conditions in aqueous solution, the first step is to:________.
natta225 [31]

Answer:

When balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.

Explanation:

Oxidation-reduction reactions or redox reactions are those in which an electron transfer occurs between the reagents. An electron transfer implies that there is a change in the number of oxidation between the reagents and the products.

The gain of electrons is called reduction and the loss of electrons oxidation. That is to say, there is oxidation whenever an atom or group of atoms loses electrons (or increases its positive charges) and in the reduction an atom or group of atoms gains electrons, increasing its negative charges or decreasing the positive ones.

The oxidation and reduction half-reactions, in a basic medium, adjust the oxygens and hydrogens as follows:

In the member of the half-reaction that presents excess oxygen, you add as many water molecules as there are too many oxygen. Then, in the opposite member, the necessary hydroxyl ions are added to fully adjust the half-reaction. Normally, twice as many hydroxyl ions, OH-, are required as water molecules have previously been added.

In short, you first adjust the oxygens with OH-, then you adjust the H with H₂O, and finally you adjust the charge with e-

So, <u><em>when balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.</em></u>

3 0
3 years ago
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