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vfiekz [6]
3 years ago
12

Water is a pure substance. Which of the following is true about water?

Chemistry
1 answer:
Nastasia [14]3 years ago
8 0

Answer:

A chemical change is required to separate the elements present in it.

Explanation:

The only true statement from the choices given is that water as a pure substance requires a chemical change to separate the elements present in it.

Water is a molecule consist of two atoms of hydrogen and one atom of oxygen.

  • The atoms are covalently bonded together.
  • A chemical process, the electrolysis of water is often used to separate the atoms of a water.
  • Physical changes cannot be used to separate the atoms of water.
  • Water is a compound which consists of two elements.

Therefore, we see that only the first choice satisfies this problem.

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Describe two techniques used to measure the PH of a solution
natali 33 [55]

Answer:

ph paper, or a ph meter

Explanation:

8 0
3 years ago
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Given the following equation: 8Fe+S8=8FeS
maxonik [38]

Answer:

a. 2954g of FeS

b. 1143g of FeS

Explanation:

Based on the reaction:

8 Fe + S₈ → 8 FeS

<em>8 moles of Fe reacts with 1 mole of S₈ to produce 8 moles of FeS</em>

<em />

a. 4.2mol sulfur produce:

4.2mol S₈ × ( 8 mol FeS / 1 mol S₈) = <em>33.6mol FeS</em>. As molar mass of FeS is 87.92g/mol, mass is:

33.6mol FeS × ( 87.92g / 1 mol FeS) = <em>2954g of FeS</em>

<em />

b. 13mol Fe produce:

13mol Fe × ( 8 mol FeS / 8 mol Fe) = <em>13mol FeS</em>. In mass:

13 mol FeS × ( 87.92g / 1 mol FeS) = <em>1143g of FeS</em>

5 0
3 years ago
Which two structures would provide a positive identification of a animal cell under a microscope
babunello [35]
Lack of cell walls no chloroplasts...hoped that helped
4 0
3 years ago
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Seawater is typically 3.5% salt and has a density of 1.03 g/mL. How many grams of salt would be needed to prepare enough seawate
Bas_tet [7]

Answer:

Amount of salt needed is around 2.3*10³ g

Explanation:

The salt content in sea water = 3.5 %

This implies that there is 3.5 g salt in 100 g sea water

Density of seawater = 1.03 g/ml

Volume of seawater = volume of tank = 62.5 L = 62500 ml

Therefore, the amount of seawater required is:

=Density*Volume = 1.03g/ml*62500ml = 6.44*10^{4} g

The amount of salt needed for the calculated amount of seawater is:

=\frac{6.44*10^{4}g\ water*3.5g\ salt }{100g\ water} =2254 g =2.3*10^{3} g

8 0
3 years ago
Which type of bond is present in hydrogen sulfide (H2S)? The table of electronegativities is given
LuckyWell [14K]

Bonds formed between atoms can be classified as ionic and covalent

Ionic bonds are formed between atoms that have a high difference in the electronegativity values.

In contrast, bonds formed between atoms that have a difference in electronegativity lower than the ionic counterparts are polar covalent bonds.  If the atoms have very similar electronegativities, they form non-polar covalent bonds.

In H2S, the S atom is bonded to 2 H atoms. The electronegativity of H = 2.2 and S= 2.56. Since the difference is not high the bond formed will be covalent (polar covalent).

7 0
3 years ago
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