She earn $55,200
92,000 * .6 =
<h2>
<u>Answer</u><u> </u><u>:</u></h2>
Option (2) and Option (3) is the correct answer .
<u>Requ</u><u>ired</u><u> </u><u>Ex</u><u>plaination</u><u> </u><u>:</u>
Scenario 2 : The height of a stone shot by a catapult reaches a maximum height and then falls on the ground.
- The graph of this scenario is a downward parabola. Therefore option 2 is correct.
Scenario 3 : The sale of product increases at first and then decreases.
- The graph of this scenario is a downward parabola. Therefore option 3 is correct.
<u>Therefore, the correct options are </u><u>2</u><u> </u><u>and</u><u> </u><u>3</u><u>.</u>
Answer:
we have 8 quarts of 40% antifreeze,
according to the britain equivalent, 1 quart = 1.13L
so, we have 8 * 1.13L = 9.04 L
out of the 9.04 L, 40% is antifreeze
amount of antifreeze = 0.4 * 9.04 = 3.616 L
moles of antifreeze present = 3.616/22.4 = 0.16 moles
moles of antifreeze in 60% solution = 0.6 * v/22.4 = 0.027 * v
<em>(where v is the volume of final solution)</em>
molarity of initial solution = 0.16/9.04 = 0.018 M
molarity of final solution = 0.027*v/v = 0.027 M
m1*v1 = m2*v2
0.018 * 9.04 = 0.027 * v
v = 0.018 * 9.04/0.027
v = 6.026 L
amount if antifreeze in the final solution = 6.026 * 0.027 =
0.163 Moles of antifreeze
amount in L = 0.163 * 22.4 = 3.65 L
amount in quarts = 3.65/1.13 = 3.23 quarts
Answer:
The statements are incorrect as: The sum of even numbers from 1 to 100(i.e. 2550) is not double\twice of the sum of odd numbers from 1 to 100(i.e. 2500).
Step-by-step explanation:
We know that sum of an Arithmetic Progression(A.P.) is given by:
where 'n' denotes the "number" of digits whose sum is to be determined, 'a' denotes the first digit of the series and '' denote last digit of the series.
Now the sum of even numbers i.e. 2+4+6+8+....+100 is given by the use of sum of the arithmetic progression since the series is an A.P. with a common difference of 2.
image with explanation
Hence, sum of even numbers from 1 to 100 is 2550.
Also the series of odd numbers is an A.P. with a common difference of 2.
sum of odd numbers from 1 to 100 is given by: 1+3+5+....+99
.
Hence, the sum of all the odd numbers from 1 to 100 is 2500.
Clearly the sum of even numbers from 1 to 100(i.e. 2550) is not double of the sum of odd numbers from 1 to 100(i.e. 2500).
Hence the statement is incorrect.
Step-by-step explanation:
