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3 years ago

Whats 0.06 in scientific notations

1 answer:

5 0

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimalplaces you move will be the exponent on the 10 . If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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An aqueous solution of cesium chloride is prepared by dissolving 52.3 g cesium chloride in 60.0g of water at 25°C. The volume of

LekaFEV [45]

Given data:

Mass of cesium chloride CsCl (m) = 52.3 g

Mass of water (mh2O)= 60.0 g

Volume of the solution (V) = 63.3 ml

Step 1: Calculate the number of moles of CsCl

Molar mass of CsCl = 168.36 g/mol

Mass of CsCl = 52.3 g

# moles = mass/molar mass = 52.3 g/168.36 g.mol-1 = 0.3106 moles

Step 2: Volume of solution in Liters

1000 ml = 1 liter

therefore, 63.3 ml corresponds to : 63.3 ml * 1 L/1000 ml = 0.0633 L

Step 3: Calculate molarity of CsCl

Molarity = moles of CsCl/volume of solution

= 0.3106 moles/0.0633 L = 4.91 moles/L

Molarity = 4.91 M

7 0

3 years ago

A 0.89% (w/v) sodium chloride solution is referred to as physiological saline solution because it has the sameconcentration of s

elixir [45]

Answer: Molarity of a physiological saline solution is 0.15 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

n = moles of solute

$V_s$ =volume of solution in ml

Given : 0.89 g of sodium chloride in 100 ml of solution.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.89g}{58.5g/mol}=0.015moles$

Volume of solution = 100 ml

$Molarity=\frac{0.015\times 1000}{100ml}=0.15M$

Molarity of physiological saline solution is 0.15 M

4 0

4 years ago

Which of the following values displays the pH of an acid? A. 3 B. 12

tester [92]

A pH of 7 or lower makes something an acid so it would be 3

3 0

3 years ago

Read 2 more answers

Predict whether each of the following reactions will occur in aqueous solutions. Explain your reasoning in each case. Note: Bari

tino4ka555 [31]

(a) sodium hydroxide + ammonium sulfate --> sodium sulfate + ammonium hydroxide

sodium sulfate precipitates in aqueous solutions

(b) niobium(V) sulfate + barium nitrate → Barium sulfate + niobium nitride

both do not precipitate in aqueous solution

(c) strontium bromide + silver nitrate ---> strontium nitrate + silver bromide

both do not precipitate in aqueous solution

3 0

4 years ago

Read 2 more answers

Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:

posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of $HNO_3$ = $\frac{15.5g}{63g/mol\times 9.5L}=0.026M$

Equilibrium concentration of $NO$ = $\frac{16.6g}{30g/mol\times 9.5L}=0.058M$

Equilibrium concentration of $NO_2$ = $\frac{22.5g}{46g/mol\times 9.5L}=0.051M$

Equilibrium concentration of $H_2O$ = $\frac{189.0g}{18g/mol\times 9.5L}=1.10M$

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$

For the given chemical reaction:

$2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)$

The expression for $K_c$ is written as:

$K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}$

$K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}$

$K_c=3.72$

Thus the value of the equilibrium constant Kc for this reaction is 3.72

5 0

3 years ago