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Effectus [21]
3 years ago
11

A student uses the apparatus to determine the concentration of a solution of hydrofluoric acid. Which component will

Chemistry
2 answers:
Marta_Voda [28]3 years ago
7 0

Answer:

1. water and a salt

2. Magnesium hydroxide reacts with HCl to produce a solution that is neutral.

3. titrant

4. 0.08 M

5. indicator

Explanation: I did it

Kryger [21]3 years ago
3 0

When determining the concentration of an acid solution, the titrant would usually be put in the burette while the analyte would be in the conical flask.

The titrant is usually a known solution while the analyte would be the unknown solution.

In order to determine the concentration of a solution of hydrofluoric acid, the acid would need to be titrated against a suitable base of known concentration using a suitable indicator to indicate the endpoint of the neutralization reaction.

Thereafter, the volume of the titrant used would be recorded and used to find the concentration of the acid (the analyte).

Thus, since the base would be known, it would be the one in the burette while the hydrofluoric acid would be the one in the conical flask.

More on titrant and analyte can be found here: brainly.com/question/22684609

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Which of the following includes a wedge.<br>A.axe<br> B.file<br>c.bolt<br>d.hammer​
faust18 [17]

The correct answers would be A, and D

3 0
3 years ago
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A 6.50x10^-5 m solution of potassium permanganate has a percent transmittance of 27.3% when measured in a 1.15 cm cell at a wave
mihalych1998 [28]
For this problem, we use the Beer Lambert's Law. Its usual equation is:

A = ∈LC
where
A is the absorbance
∈ is the molar absorptivity
L is the path length
C is the concentration of the sample solution

As you notice, we only have to find the absorbance. But since we are not given with the molar absorptivity, we will have to use the modified equation that relates % transmittance to absorbance:

A = 2 - log(%T)
A = 2 - log(27.3)
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7 0
3 years ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
Brums [2.3K]

Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

7 0
4 years ago
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Slav-nsk [51]

Answer:

copper metal and steel metak

3 0
3 years ago
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NEED ANSWER FAST
Anarel [89]

Answer: Option (c) is the correct answer.

Explanation:

When current passes through a wire then a magnetic field is formed. Therefore, when two wires carry current in the same direction then both the wires with have respective magnetic fields in the same direction and their total magnetic field will be large.

But when current between two wires flow in opposite direction then the magnetic field produced will also be in opposite direction. Therefore, both the magnetic fields cancel each other out. Thus, total magnetic field will be small.

As a result, wires which carry current in the opposite direction repel each other.


5 0
4 years ago
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