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3 years ago

A student uses the apparatus to determine the concentration of a solution of hydrofluoric acid. Which component will

Chemistry

2 answers:

Marta_Voda [28]3 years ago

7 0

Answer:

1. water and a salt

2. Magnesium hydroxide reacts with HCl to produce a solution that is neutral.

3. titrant

4. 0.08 M

5. indicator

Explanation: I did it

Kryger [21]3 years ago

3 0

When determining the concentration of an acid solution, the titrant would usually be put in the burette while the analyte would be in the conical flask.

The titrant is usually a known solution while the analyte would be the unknown solution.

In order to determine the concentration of a solution of hydrofluoric acid, the acid would need to be titrated against a suitable base of known concentration using a suitable indicator to indicate the endpoint of the neutralization reaction.

Thereafter, the volume of the titrant used would be recorded and used to find the concentration of the acid (the analyte).

Thus, since the base would be known, it would be the one in the burette while the hydrofluoric acid would be the one in the conical flask.

More on titrant and analyte can be found here: brainly.com/question/22684609

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3 years ago

If you are given the molarity of a solution, what additional information would you need to find the weight/weight percent (w/w%)

Ludmilka [50]

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- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

Explanation:

Hello,

In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

For instance, if a 1-M solution of HCl has a density of 1.125 g/mL, we can compute the w/w% as follows:

$w/w\%=1\frac{molHCl}{L\ sln}*\frac{36.45gHCl}{1molHCl}*\frac{1L\ sln}{1000mL\ sln}*\frac{1mL\ sln}{1.125g\ sln} *100\%\\\\w/w\%=3.15\%$

Whereas the first factor corresponds to the molar mass of HCl, the second one the conversion from L to mL of solution and the third one the density to express in terms of grams of solution.

Regards.

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