1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr1967 [171]
3 years ago
5

What is the molar solubility of marble (i.e., [ca2 ] in a saturated solution in normal rainwater, for which ph=5.60? express you

r answer to?
Chemistry
1 answer:
Brut [27]3 years ago
6 0
Missing in your question :

Ksp of(CaCO3)= 4.5 x 10 -9

Ka1 for (H2CO3) =  4.7 x 10^-7

Ka2 for (H2CO3) = 5.6 x 10 ^-11

1) equation 1 for Ksp = 4.5 x 10^-9 

CaCO3(s)→ Ca +2(aq)    +  CO3-2(aq)  

2) equation 2 for Ka1 = 4.7 x 10^-7

 H2CO3 + H2O → HCO3- + H3O+

3) equation 3 for Ka2 = 5.6 x 10^-11

 HCO3-(aq) + H2O(l) → CO3-2 (aq)  + H3O+(aq)

so, form equation 1& 2&3 we can get the overall equation:
CaCO3(s)  +  H+(aq)  → Ca2+(aq)   + HCO3-(aq)

note: you could get the overall equation by adding equation 1 to the inverse of equation 3 as the following:
when the inverse of equation 3 is :

CO3-2 (aq) + H3O+ (aq) ↔ HCO3- (aq) + H2O(l)  Ka2^-1 = 1.79 x 10^10
when we add it to equation 1
CaCO3(s) ↔ Ca2+(aq)  +  CO3-2(aq)   Ksp = 4.5 x 10^-9

∴ the overall equation will be as we have mentioned before:
when H3O+ = H+

CaCO3(s) + H+(aq)  ↔ Ca2+ (aq) + HCO3-(aq)   K= 80.55

from the overall equation:

∴K = [Ca2+][HCO3-] / [H+]

when we have [Ca2+] = [HCO3-] so we can assume both = X

∴K = X^2 / [H+]

when we have the PH = 5.6 so we can get [H+]

PH = - ㏒[H+]
5.6 = -㏒[H]
∴[H] = 2.5 x 10^-6

so, by substitution on K expression:

∴ 80.55 = X^2 / (2.5 x10^-6)

∴X = 0.0142

∴[Ca2+] = X = 0.0142 
You might be interested in
2) Examine the molecules below.<br> Circle the molecules that can also be classified as compounds.
sergejj [24]

Answer:

3rd

Explanation:

its the way they look

4 0
2 years ago
What happens when sodium and sulfur combine
german

Answer:

It emits hydrogen sulfide...smells like rotten eggs..

ty:)pls let me know whether this is ryt:D

6 0
3 years ago
Read 2 more answers
Which type of wave does not require a medium to travel through?
nlexa [21]

Hello,

I'm not very sure but I think the correct answer is D) Water Wave

I really hope this helps!!!! Happy Holidays!!!! (:

8 0
3 years ago
A compound with a molar mass of 102.133 g/mol contains an element with a subscript of 5 . the element is 58.80 g per 100.0 g com
VLD [36.1K]

Answer:

12.0108408

Explanation:

Denote the element with a letter like say X. Since it has a subscript of 5, then, X5.

Molecular mass=102.133g/mol.

% of X in compound =58.8/100

=0.588

Mass of X in the compound = 0.588*102.133 ( the % of X in compound * molar mass of compound)

= 60.054204

X5=60.054204

Then element X has a mass of 60.054204/5=12.0108408

6 0
3 years ago
In a mixture of gases exerting a total pressure of 2.50 atm, carbon dioxide has a mole fraction of 0.450. What is the partial pr
AlladinOne [14]

Answer:

1.12 atm is the correct answer

3 0
3 years ago
Other questions:
  • Given the balanced equation:
    14·1 answer
  • If the half-reaction: Fe3+ + e- = Fe2+ were chosen as the standard reduction potential table reference instead of: 2H+ + 2e- = H
    10·1 answer
  • Which formula is a molecular compound
    6·1 answer
  • The chemical reaction shown above takes place in a closed system. What is true about the system while the reaction occurs? A. Th
    11·1 answer
  • Which of these tasks falls under the responsibility of a forensic scientist?
    7·1 answer
  • I need the answer please
    13·2 answers
  • Question 4(Multiple Choice Worth 4 points)
    5·1 answer
  • Which of the following is NOT true about wastewater and wastewater treatment?
    8·1 answer
  • Drinking energy drinks makes people more aggressive.
    10·1 answer
  • What is the orbital hybridization of a central atom that has one lone pair and bonds to:
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!