Need help on this on 6 and 7

Does an eclipse occur every time the moon is in the new or full moon phase?

harina [27]

Answer:

solar eclipse mostly occurs when the moon gets between Earth and the sun, and the moon casts a shadow over Earth. A solar eclipse can only take place at the phase of new moon, when the moon passes directly between the sun and Earth and its shadows fall upon Earth's surface.

7 0

3 years ago

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A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling

Natalka [10]

Answer:

H = 5 m

Explanation:

As the person leaves the slide horizontally so the time taken by the person to hit the water is given as

$t = 0.672 s$

so we can find the vertical velocity by which person will hit the water using kinematics

$v_y = u_y + at$

$v_y = 0 + (9.81)(0.672)$

$v_y = 6.6 m/s$

now the speed of the person at the end of the slide is given as

$v = \frac{L}{t}$

$v = \frac{5}{0.672}$

$v_x = 7.44 m/s$

now by energy conservation we can find the initial height

$mgH = \frac{1}{2}m(v_x^2 + v_y^2)$

$H = \frac{1}{2g}(v_x^2 + v_y^2)$

$H = \frac{1}{2(9.81)}(7.44^2 + 6.6^2)$

$H = 5 m$

6 0

3 years ago

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Lars is standing near the edge of a 90-meter cliff. He throws a ball upward, but does not catch it, and it falls to the bottom o

Kipish [7]

Answer:

c. 43 m/s

Explanation:

Given the following data;

Displacement, S = 90 meters

Time, t = 5.55 seconds

To find the initial velocity;

We would use the second equation of motion given by the formula;

$S = ut + \frac {1}{2}at^{2}$

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

We know that acceleration due to gravity is -9.8m/s² because the direction is downward.

Substituting into the equation, we have;

$90 = u*5.55 + \frac {1}{2}*(-9.8)*5.55^{2}$

$90 = u5.55 - 4.9*30.8025$

$90 = u5.55 - 150.93225$

Rearranging the equation, we have;

$u5.55 = 90 + 150.93225$

$u5.55 = 240.93225$

$u = \frac {240.93225}{5.55}$

Initial velocity, u = 43.41 ≈ 41 m/s

4 0

3 years ago

How will a current change if the voltage in a circuit is held constant while the resistance doubles? 1. it's impossible to predi

laila [671]

According to Ohm's Law:

$I = \frac{V}{R}$

Where: V = Voltage
I = Current
R = Resistance

As you can see here, you can say that Current is directly proportional to Voltage and indirectly proportional to Resistance. This means that as the voltage increases, current increases and as the resistance increases, current decreases.

So in your scenario, if the voltage remains the same, but the resistance is doubled, that means that the current will be halved. So the answer to your question is 2. the current will drop to half of its original value.

4 0

3 years ago

What velocity will a freefalling object have after falling 80 meters

vovangra [49]

Answer:

129.96

At a Gravitational acceleration of 32.17405 ( which is the normal rate for a freefall) you will geta velocity of 129.96 and the time of fall will be 4.039 seconds from 80 meters.

Why is the weight of a free falling body zero? It is not, an object in free fall will still have a weight, governed by the equation W = mg, where W is the object's weight, m is the object's mass, and g is acceleration due to gravity. Weight, however, has no effect on an objects free falling speed, two identically shaped objects weighing a different amount will hit the ground at the same time.

Hope this helps!! If so please mark brainliest and rate/heart to help my account if it did!!

6 0

3 years ago