Answer:
b) Springs oscillate with the same frequency,
Explanation:
expression for frequency of vibration of mass hanging from a spring is given as follows
f =
k is force constant of spring and m is mass vibrating .
In the present case, if mass stretches the spring by x and remains balanced
mg = k x
g and x are same for both cases
will also be same for both cases .
Hence frequency of vibration will also be same for both the balls .
The law of equal areas suggests that planets move fastest when at "perihelion" at slowest when at the "aphelion." Perihelion refers to the point at a planet's orbit, comet or asteroid where it is closest to the sun. Aphelion <span>refers to the point at a planet's orbit, comet or asteroid where it is furthest to the sun.</span>
The answer is B. Have a good day! :)
Answer:
The activity of cobalt-60 after 72 hours is 34.895 MBq
Explanation:
A(t) = Ao(0.5)^t/t1/2
A(t) is the activity of cobalt-60 after time t
Ao is the initial activity of cobalt-60 = 35 MBq
t is time taken to reduce in activity = 72 hours = 72/24 = 3 days
t1/2 is the half-life = 0.693 ÷ decay constant = 0.693 ÷ 0.001/day = 693 days
A(72) = 35(0.5)^3/693 = 35 × 0.5^0.00433 = 35 × 0.997 = 34.895 MBq
Answer:
With a slower speed-perhaps 5 cm/s answer is c