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SOVA2 [1]
4 years ago
13

Which statement describes the gravitational force and the electrostatic force between two charged particles?

Physics
2 answers:
Rudik [331]4 years ago
6 0
I believe the answer is. <span>the gravitational force must be attractive, whereas the electrostatic force may be either attractive or repulsive. </span>
inessss [21]4 years ago
5 0
Force is a vector quantity & must<span> be treated accordingly; the </span>electric force between two<span> objects always acts along the line that connects their centers of </span>charge<span> ... </span>Electric forces can<span> be </span>either attractive<span> or</span>repulsive<span>, but </span>gravitational forces<span> are always </span>attractive<span> (because objects </span>can<span> have </span>either<span> a positive or a negative </span>charge<span>, .</span>
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Suppose you sound a 1056-hertz tuning fork at the same time you strike a note on the piano and hear 2 beats/second. You tighten
Sindrei [870]

Answer:

The frequency of the piano string is either 1053 HZ or 1059 HZ.

Explanation:

Here we know that frequency of beats is equal to the difference between the frequencies between two waves .

     Given that frequency of tuning fork is 1056 HZ  .

     Let the frequency of the piano be ' f ' .

   Given that number of beats = 3.

    We know that   | 1056 - f | = 3 ;

                      ⇒       1056- f = ±3,

         Upon solving this we get  

                        f = 1056-3 and 1056 + 3

                   ⇒ f = 1053 or 1059 .

                     

6 0
3 years ago
What are three physical properties of gases
NikAS [45]

Answer:   Gases have three characteristic properties: (1) they are easy to compress, (2) they expand to fill their containers, and (3) they occupy far more space than the liquids or solids from which they form. An internal combustion engine provides a good example of the ease with which gases can be compressed.

Explanation:

7 0
3 years ago
Gold has a density of 19.32 g/cm3. what is the volume of a sample of gold with a mass of 27.63 grams?
schepotkina [342]
Answer:  The volume is:  " 1.430 cm³ " .
_____________________________
Explanation:  
________________________
Volume, " V  = ? ; (unknown, we need to solve for this).
Density,  "D  = 19.32 g / cm³ ; 
mass , "m" = 27.63 g ; 
_____________________________________________
The formula for density is:  
____________________________________________
  D = m / V ;   Divide each side of the equation by:  "(1/m)" ;
                    to isolate " V" on one side of the equation; and to solve for "V" ; 
____________________________________________
1/m)*D = (1/m) * (m / V) ;
_______________________________
    to get:   
_______________________________
       D/m = ; ↔  1 / V ;  Take the reciprocal of EACH SIDE; to isolate "V" on each side of the equation:    
_____________________________
      m / D = V/1 ↔ V = m / D ;
_____________________________
    V = m / D ; 
_______________________________
         Now, plug in our given values for mass, "m" ; and Density, D";              to solve for "Volume, V " ;
_____________________________________
    V  =  m / D  =  (27.63 g)  ÷  (<span>19.32 g / cm</span>³)  ;                
 
                       =  (27.63 g) * (1 cm³ / 19.32 g) ;
 
                       =   (27.63 ÷ 19.32)  cm³  ;
  
                       =   1.4301242236024845 cm³ ;

                                              → Round to "4 significant figures" ; 
                       =   1.430 cm³ .
____________________________________________
   The volume is:  " 1.430 cm³ " .
______________________________________________
4 0
3 years ago
When a car of mass 1200 kg, going with speed 30 m/s, rounds an unbanked curve of radius 150 m, what is the minimum coefficient o
Nana76 [90]

Answer:

\mu_s=0.61

Explanation:

In order for the car does not slip, the frictional force must be equal to the centripetal force due to the circular motion. According to the free body diagram:

\sum F_y:N=mg\\\sum F_x:F_f=F_c

The frictional force is given by:

F_f=\mu_s N=\mu_s mg

The centripetal force is defined as:

F_c=ma_c=m\frac{v^2}{r}

Here v is the linear speed and r is the radius of the circular motion. Replacing this equations:

\mu_smg=m\frac{v^2}{r}\\\mu_s=\frac{v^2}{gr}\\\mu_s=\frac{(30\frac{m}{s})^2}{(9.8\frac{m}{s^2})(150m)}\\\mu_s=0.61

8 0
4 years ago
As frequency increases, what happens to the tone (or pitch) of a sound? Which option is it?
icang [17]

Answer:

gets higher

Explanation:

There are videos that show the range of human hearing.  If you would play the video, you would notice that if the frequency increases, the pitch would also increase.

3 0
4 years ago
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