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3 years ago

In cats, short hair is dominant and long hair is recessive. If a cat has the genotype of hh, what type of hair will it have?

Physics

1 answer:

raketka [301]3 years ago

8 0

Answer:

long hair

Explanation:

long hair = hh

short hair= HH

and medium= Hh

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A small ball (mass of 0.5 kg) and a large brick (mass of 10 kg) are dropped from a height of 5 meters. Both items are released a

Anna71 [15]

Explanation:

neglecting air resistance both will land at the same moment.

both have therefore the same acceleration.

7 0

3 years ago

Read 2 more answers

A stationary horn emits a sound with a frequency of 228 Hz. A car is moving toward the horn on a straight road with constant spe

stiks02 [169]

Answer: 26.84 m/s

Explanation:

Given

Original frequency of the horn $f_o=228\ Hz$

Apparent frequency $f'=246\ Hz$

Speed of sound is $V=340\ m/s$

Doppler frequency is

$\Rightarrow f'=f_o\left(\dfrac{v+v_o}{v-v_s}\right)$

Where,

$v_o=\text{Velocity of the observer}\\v_s=\text{Velocity of the source}$

Insert values

$\Rightarrow 246=228\left[\dfrac{340+v_o}{340-0}\right]\\\\\Rightarrow 366.84=340+v_o\\\Rightarrow v_o=26.8\ m/s$

Thus, the speed of the car is $26.84\ m/s$

4 0

3 years ago

How do you find the mechanical advantage of a wheel and axle

alexandr1967 [171]

Answer: <em>In order to calculate the mechanical advantage of a wheel and axel, you can divide the radius of the wheel by the radius of the axle. If a wheel's radius is 60cm and its axle is 30cm, what is the mechanical advantage of the wheel and axle? The output force of the wheel and axle is 2 times greater than the input force.</em>

<em />

7 0

4 years ago

2. A 200.0-kg bear grasping a vertical tree slides down at constant velocity. What is the friction force between the tree and th

Neporo4naja [7]

Answer: 1960 N

Explanation:

The bear is sliding down at constant velocity: this means that its acceleration is zero, so the net force is also zero, according to Newton's second law:

$F_{net}=ma=0$

There are two forces acting on the bear: its weight W, pulling downward, and the frictional force Ff, pulling upward. Therefore, the net force is given by the difference between the two forces:

$F_{net}=W-F_f=0$

From the previous equation, we find that the frictional force is equal to the weight of the bear:

$F_f=W=mg=(200.0 kg)(9.8 m/s^2)=1960 N$

8 0

3 years ago

A violin string is 45.0 cm long and has a mass of 0.242 g. When tightened on the neck of the violin, the distance between the pi

stiks02 [169]

Answer:

The tension is 75.22 Newtons

Explanation:

The velocity of a wave on a rope is:

$v=\sqrt{\frac{TL}{M}}$ (1)

With T the tension, L the length of the string and M its mass.

Another more general expression for the velocity of a wave is the product of the wavelength (λ) and the frequency (f) of the wave:

$v= \lambda f$ (2)

We can equate expression (1) and (2):

$\sqrt{\frac{TL}{M}}$ = $\lambda f$

Solving for T

$T= \frac{M(\lambda f)^2}{L}$ (3)

For this expression we already know M, f, and L. And indirectly we already know λ too. On a string fixed at its extremes we have standing waves ant the equation of the wavelength in function the number of the harmonic $N_{harmonic}$ is:

$\lambda_{harmonic}=\frac{2l}{N_{harmonic}}$

It's is important to note that in our case L the length of the string is different from l the distance between the pin and fret to produce a Concert A, so for the first harmonic:

$\lambda_{1}=\frac{2(0.425m)}{1}=0.85 m$

We can now find T on (3) using all the values we have:

$T= \frac{2.42\times10^{-3}(0.85* 440)^2}{0.45}$

$T=75.22 N$

3 0

4 years ago