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joja [24]
3 years ago
9

A 50 g dart rests up against a spring that has been compressed 0.04 meters. It has a spring constant of 1560 N/m.What is the max

imum velocity of the dart after the spring has transferred all its energy to it.
Physics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

The maximum velocity of the dart after the spring has transferred all its energy to it is 7.06 m/s.  

Explanation:

Given that,

Mass of the dart, m = 50 g = 0.05 kg

Compression in the spring, x = 0.04 m

Spring constant, k = 1560 N/m

We need to find the maximum velocity of the dart after the spring has transferred all its energy to it. The kinetic energy is converted to elastic potential energy as :

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

v=\sqrt{\dfrac{kx^2}{m}} \\\\v=\sqrt{\dfrac{1560\times (0.04)^2}{0.05}} \\\\v=7.06\ m/s

So, the maximum velocity of the dart after the spring has transferred all its energy to it is 7.06 m/s.

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Explanation:

Answer: 81.6 m.

The time it takes gravity to slow 40 m/s to zero when it teaches maximum height is

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The height reached is the average velocity times this time 4.08 s, with v(avg) = [v(initial) + v(final)] / 2 with v(final) = 0. v(avg) = v(initial) / 2 = 40 m/s / 2 = 20 m/s.

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