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myrzilka [38]
3 years ago
8

Two balls are on a frictionless horizontal tabletop. Ball x initially moves at 10 meters per second, as shown in Figure 1 above.

It then collides elastically with identical ball Y which is initially at rest. After the collision, ball x moves at 6 meters per second along a path at 53 degrees to its original direction, as shown in Figure 2 above, Which of the following diagrams best represents the motion of ball Y after the collision?

Physics
1 answer:
Marizza181 [45]3 years ago
8 0

Answer:

Option (B)

Explanation:

We know that without any external force velocity of center of mass must be same. So, velocity of Center of Mass of balls must be in same direction as that of Ball X.

So, velocity of center of mass perpendicular to the direction of initial must be zero.

As given in question after collision ball X moves with velocity 6 mps with an angle 53° with its initial path. So velocity of ball X in perpendicular direction is \frac{24}{5}

Hence the perpendicular component of ball Y must be \frac{24}{5}

By checking We get that option (B) satisfy the condition.

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Answer:

The value is t = 689.029 \  hours

Explanation:

From the question we are told that

The molar mass of hydrazine is Z =  32 g/mol = \frac{32}{1000} = 0.032 \  kg/mol

The initial temperature is T_i  =  -186 ^o F = (-186-32) *\frac{5}{9} +273.15 = 152\ K

The final temperature is T_f  =  78 ^o F = (78-32) *\frac{5}{9} +273.15 = 298.7 \ K

The specific heat capacity is c_h  =  0.099 [kJ/(mol K)] = 0.099 *10^3 J/(mol/K)

The power available is P = 300 \ W

The mass of the fuel is m =   1640 \  kg

Generally the number of moles of hydrazine present is

n  =  \frac{m}{Z}

=> n  =  \frac{1640}{= 0.032}

=> n  =  51250 \ mol

Generally the quantity of heat energy needed is mathematically represented as

Q =  n * c_h * (T_f -T_i)

=> Q =  51250  * 0.099 *10^3  * (298.7 - 152)

=> Q =  7.441516913 * 10^{8} \  J

Generally the time taken is mathematically represented as

t =  \frac{Q}{P}

=> t =  \frac{7.441516913 * 10^{8} }{300}

=> t = 2480505.6377 s

Converting to hours

t = \frac{2480505.6377}{3600}

=> t = 689.029 \  hours

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The specific heat capacity of ethanol is 2440J/kg °C. How many joules of energy will be required to heat 150g ethanol to 35°C if
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Answer:

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Explanation:

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