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vfiekz [6]
3 years ago
5

What are the steps for using a compass and straightedge to construct a square?   Drag and drop the steps in order from start to

finish.
Use the straightedge to draw FD ¯ ¯ ¯ ¯ ¯ and FE ¯ ¯ ¯ ¯ ¯ .

Keeping the same compass width, place the compass on point E and draw an arc in the interior of ∠DBE to intersect the previously drawn arc. Label the point of intersection as point F.

Use a straightedge to draw line t and label a point on the line as point B.

Without changing the compass width, place the compass point on point D and draw an arc in the interior of ∠DBE .

With the compass open to the desired side length of the square, place the compass point on point B and draw an arc on line t and an arc on BC ← → . Label the points of intersection as points D and E.

Construct a line perpendicular to line t through point B. Label a point on this line as point C.
Mathematics
2 answers:
denis-greek [22]3 years ago
6 0
Is this from Flvs? if so i can help you
Firlakuza [10]3 years ago
6 0

Answer:

See explanation below.

Step-by-step explanation:

To construct a square using only a compass and a straightedge first we need to:

  1. Use a straightedge to draw  a line (we will name the line t) and label a point on the line as point B.
  2. Then, you will draw a perpendicular line to the segment that passes through point B ( To remember how to draw a perpendicular line through a segment see the note at the end of the explanation), label a point on this line as point C.
  3. With the compass open to the desired side length of the square (meaning the measure of the side of the square you need), place the compass point on point B and draw an arc on line t and an arc on BC. Label the points of intersection as points D and E.
  4. Without changing the compass width, place the compass point on point D and draw an arc in the interior of ∠DBE .
  5. Keeping the same compass width, place the compass on point E and draw an arc in the interior of ∠DBE to intersect the previously drawn arc. Label the point of intersection as point F.
  6. Finally, use the straightedge to draw FD and FE (the other two sides of the square are DB and DE)

<u>*Note: To draw a perpendicular line through a segment follow the next steps:</u>

  1. Place the compass point at point B
  2. Draw an arc of ANY size that crosses line t twice (one to the left of point B and one to the right)
  3. Stretch the compass larger than you first did and place the point at one of the points where the previous arc crossed the line.
  4. Draw an arc above the line.
  5. Using the same width you used on step 3, place the compass point at the other point in the line.
  6. From there draw an arc above the line that crosses the other arc from step 4.
  7. Using your straightedge draw a line from the intersection of both arcs and point B and this line will be perpendicular to the line and it will pass through point B.
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juin [17]
Calculate the circumference of the full circle:

circumference = PI x diameter = 3.14 x 20 = 62.8 inches
 the arc length is 160 degrees of the full circle

divide 160 by 360 (full circle) and multiply by the circumference:

160/360 x 62.8 = 27.9 inches

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3 years ago
152.5 is 250% of what number
MakcuM [25]
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3 years ago
Suppose the scores on an exam are normally distributed with a mean μ = 75 points, and standard deviation σ = 8 points.
Artyom0805 [142]

Answer:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z>\frac{69-75}{8})=P(Z>-0.75)

And we can find this probability on this way:

P(Z>-0.75)=1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problm

Let X the random variable that represent the scores on an exam of a population, and for this case we know the distribution for X is given by:

X \sim N(75,8)  

Where \mu=75 and \sigma=8

We are interested on this probability

P(X>69)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z>\frac{69-75}{8})=P(Z>-0.75)

And we can find this probability on this way:

P(Z>-0.75)=1-P(Z

4 0
3 years ago
Write an equation of the line in slope-intercept form.
Ainat [17]

Answer:

y = 1/3x + 2

or

f(x) = 1/3x + 2

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3 years ago
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