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Triss [41]
3 years ago
6

How many servings in a pound of spaghetti?

Mathematics
1 answer:
Marrrta [24]3 years ago
4 0
It may be up to 3 thru 7
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Divide. Write the quotient in lowest terms. 1/4 ÷ 1 1/8<br><br> ​
natta225 [31]

Answer:2/11

Step-by-step explanation:

A fraction is in simplest form when the top and bottom cannot be any smaller

Firstly start by getting the common factors between 1 and 4 in 1/4 and 11 and 8 in 11/8. The common factor is 1 in 1/4 and 1 in 11/8. 1÷1/4÷1= 1/4. 11÷1/8÷1 = 11/8.

1/4÷ 11/8 =2/11.

3 0
3 years ago
Read 2 more answers
What is the solution to the inequality - 6x + 5 &gt; -1
ExtremeBDS [4]

[ Answer ]

\boxed{X \ < \ 1}

[ Explanation ]

  • Solution To Inequality: - 6x + 5 > -1

-------------------------------------

  • Subtract 5 From Both Sides

- 6x + 5 - 5 > -1 - 5

  • Simplify

-6x > -6

  • Multiply Both Sides By -1 (Reverse Inequality)

(-6x)(-1) < (-6)(-1)

  • Simplify

6x < 6

  • Divide Both Sides By 6

\frac{6x}{6} < \frac{6}{6}

  • Simplify

X < 1

\boxed{[ \ Eclipsed \ ]}

4 0
3 years ago
How would you do this???
Kobotan [32]

Answer:

8.3 L/s

Step-by-step explanation:

To find the answer you need to find the slope also known as the rate of change. When you find slope it is always change in y over change in x.

\frac{399-150}{40-10}

Then simplify

\frac{249}{30}

Then divide to get your slope/average rate of change

\frac{249}{30} = 8.3

6 0
3 years ago
Which description is correct for the x-intercept(s) of Function A and Function B?
ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

Generally,

A straight line equation is given as

y = mx + c

Where,

m is the slope or gradient of the line

c is the intercept of y axis, when x = 0

Now,

Given the function A

g(x) = 0 7 0 2 -2

x = -2 3. 5 -1 0

So, we said the intercept c is when x = 0,

Therefore, in this case when x=0, g(x) = -2

Then, the intercept is -2 on y axis

Then, it has only one intercept, which is -2 on y-axis

To get the intercept on x axis, we will set y to zero,

In this case,

g(x) = 0, then, we have the intercept on x-axis to be -2 and 5

So it has 2-intercept on x axis, one positive and one negative

Given the function B

F(x) = |x| - 3

Comparing this to equation of a line, y= mx + c,

Then we notice that, the intercept is -3

Then, it has only one intercept which is -3 on y axis.

Now, to get the intercept on x axis, we will set f(x) = 0

F(x) = |x| - 3

0 = |x| - 3

Then, |x| = 3

Then, x = 3 or -x =3

Note that, |x| means x and -x

Then, x = 3 or x = -3

So it has also two intercept on the x axis, one positive and one negative.

Then, the third option is the correct option

Both functions have one negative and one positive x-intercept.

5 0
3 years ago
A survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10. (a)
skad [1K]

Answer:

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b) The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

<u>Step-by-step explanation</u>:

Step:-(i)

Given data a survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10

The sample size 'n' = 25

The mean of the sample   x⁻  = $28

The standard deviation of the sample (S) = $10.

Level of significance ∝=0.05

The degrees of freedom γ =n-1 =25-1=24

tabulated value t₀.₀₅ = 2.064

<u>Step 2:-</u>

The 95% of confidence intervals for the average spending

((x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )

(28 - 2.064 \frac{10}{\sqrt{25} } ,28 + 2.064\frac{10}{\sqrt{25} } )

( 28 - 4.128 , 28 + 4.128)

(23.872 , 32.128)

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b)

Null hypothesis: H₀:μ<30

Alternative Hypothesis: H₁: μ>30

level of significance ∝ = 0.05

The test statistic

t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

t = \frac{28-30 }{\frac{10}{\sqrt{25} } }

t = |-1|

The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

<u>Conclusion</u>:-

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

8 0
3 years ago
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