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Citrus2011 [14]
3 years ago
9

Which of the following substances would you expect to have a low melting point?

Chemistry
1 answer:
Lorico [155]3 years ago
5 0
The substance you would expect to have a low melting point would be carbon dioxide, so the correct answer would be A
You might be interested in
All elements have a AHf, of ___
stellarik [79]

All elements have a AHf, of <u>0</u>

kJ/mole at standard temperature and pressure.

<h3>What is an element?</h3>

An element can be defined as a substance which cannot be split into two or more simpler forms by an ordinary chemical process

Below are the list of the first twenty elements:

  • Hydrogen
  • Helium
  • Lithium
  • Berylium
  • Boron
  • Carbon
  • Nitrogen
  • Oxygen
  • Fluorine
  • Neon
  • Sodium
  • Magnesium
  • Aluminum
  • Silicon
  • Phosphorus
  • Sulphur
  • Chlorine
  • Argon
  • Potassium
  • Calcium

So therefore, all elements have a AHf, of <u>0</u>

kJ/mole at standard temperature and pressure.

Learn more about elements:

brainly.com/question/11829854

#SPJ1

7 0
2 years ago
Toluene (C6H5CH3 ), an organic compound often used as a solvent in paints, is mixed with a similar organic compound, benzene (C6
Sergeeva-Olga [200]

Explanation:

The given data is as follows.

 Weight of solute = 75.8 g,   Molecular weight of solute (toulene) = 92.13 g/mol,    volume = 200 ml

  • Therefore, molarity of toulene is calculated as follows.

      Molarity = \frac{\text{weight of solute}}{\text{molecular weight of solute}} \times \frac{1000}{\text{volume of solution in ml}}

                    = \frac{75.8 g}{92.13 g/mol} \times \frac{1000}{200 ml}

                    = 4.11 M

Hence, molarity of toulene is 4.11 M.

  • As molality is the number of moles of solute present in kg of solvent.

So, we will calculate the molality of toulene as follows.

   Molality = \frac{\text{given weight of solute}}{\text{given molecular weight of solute}} \times \frac{1000}{\text{weight of solvent in grams}}

             = \frac{75.8 g}{92.13 g/mol} \times \frac{1000}{95.6 g}

             = 8.6 m

Hence, molality of given toulene solution is 8.6 m.

  • Now, calculate the number of moles of toulene as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{75.8 g}{92.13 g/mol}

                             = 0.8227 mol

Now, no. of moles of benzene will be as follows.

     No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{95.6 g}{78.11 g/mol}

                             = 1.2239 mol

Hence, the mole fraction of toulene is as follows.

         Mole fraction = \frac{\text{moles of toulene}}{\text{total moles}}

                             = \frac{0.8227 mol}{(0.8227 + 1.2239) mol}

                             = 0.402

Hence, mole fraction of toulene is 0.402.

  • As density of given solution is 0.857 g/cm^{3} so, we will calculate the mass of solution as follows.

         Density = \frac{mass}{volume}

     0.857 g/cm^{3} = \frac{mass}{200 ml}      (As 1 cm^{3} = 1 g)

                      mass = 171.4 g

Therefore, calculate the mass percent of toulene as follows.

      Mass % = \frac{\text{mass of solute}}{\text{mass of solution}} \times 100

                   = \frac{75.8 g}{171.4 g} \times 100

                   = 44.22%

Therefore, mass percent of toulene is 44.22%.

8 0
4 years ago
Need some help with this problem please!
Tom [10]

Answer:

18 liters

Explanation:

Step 1: Figure out what the formula and what you are dealing with.

- 25 degrees celcius is constant, so it is irrelevant for the mathmatical part.

- P1 = 1 atm

- P2 = 20 atm

- V1 = 360 liters

- V2 = trying to find

Note: remember the original equation is V1/P1 = V2/P2

- Step 2: Rearrange the equation to fit this problem, you should get...

V2 = V1 x P1 / P2

- Step 3: Fill our own numbers in. You should get...

360 L x 1 atm / 20 atm = 18 Liters (do the math)

- Answer = 18 Liters

- Remember to just follow the formula and fill it in with your own numbers.

If you need any more help comment below. I am happy to help anytime.

7 0
3 years ago
How does this look? (Its for a science project about animal life
konstantin123 [22]

Answer:

why is there a cherry on its head?

Explanation:

You may want to add details/description to the photo as it is a little confusing

3 0
3 years ago
Read 2 more answers
Determine the vapor pressure (atm) of rubbing alcohol (isopropanol) at 20.0 °C. The normal boiling point of isopropanol is 82.3
jeyben [28]
Here we apply the Clausius-Clapeyron equation:
ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁)

The normal vapor pressure is 4.24 kPa (P₁)
The boiling point at this pressure is 293 K (P₂)
The heat of vaporization is 39.9 kJ/mol (ΔH)
We need to find the vapor pressure (P₂) at the given temperature 355.3 K (T₂)

ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293)
P₂ = 101.2 kPa
8 0
3 years ago
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