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Citrus2011 [14]
2 years ago
9

Which of the following substances would you expect to have a low melting point?

Chemistry
1 answer:
Lorico [155]2 years ago
5 0
The substance you would expect to have a low melting point would be carbon dioxide, so the correct answer would be A
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A tank of water was contaminated with a colored dye (D). To determine the concentration of D, an analyst took 5.0-mL solution fr
alekssr [168]

Answer:

0.005 M

Explanation:

Given data:

volume of sample solution ( volume of D ) = 5.0 mL

volume of added stock solution ( V1 ) = 5.0 mL

concentration of added stock solution ( N1 )  = 0.02 M

Total volume of concentration  ( V2 )= 10 mL = ( 5.0 mL + 5.0mL)

concentration of Total volume of sample ( C2 ) = 0.01

N2 = ( N1V1 ) / V2

     = ( 0.02 * 5 ) / 10 = 0.01 m

absorbance of sample solution ( A1 ) = 0.10

absorbance of additional sample solution ( A2 ) = 0.20

attached below is the remaining part of the detailed solution

3 0
2 years ago
If the empirical formula of a compound is C2H5 and the Molecular mass is 87g/mol what is the molecular formula?
frez [133]
C6H15, C2H5 has a molar mass of 29g/mol. 87 divided by 29 is 3. Then multiply each element subscript by 3
6 0
3 years ago
For the oxidation-reduction reaction equation given here 4ga+p4 indicate how many electrons are transferred in the formation of
sergij07 [2.7K]
The reaction given is:

4Ga + P4 ---> 4GaP

The oxidation number of the reactants is zero, because they are pure elements.

The P in compounds may have oxidation states 3- or 5-. Gallium may only have oxidation state 3+.

Then, to be neutral in GaP the oxidation states are 3+ for Ga and 3- for P.

And the transference of electrons can be see in this oxidation - reduction equations:

Ga (0) - 3 e-    ----> Ga (3+)

P (0) + 3e- ---> P (3-)

So, for one formula unit, 3 electrons have been transfered from each Ga atom to P atom to form one GaP unit.

Answer: 3 electrons.
3 0
3 years ago
If body fats has a density of 0.94 g/mL and 3.0 liters of fat are removed, how many pounds of fat were removed from the patient?
-Dominant- [34]

Answer:

6.217 pounds

Explanation:

We are given;

  • Density of body fats 0.94 g/mL
  • Volume of fats removed = 3.0 L

We are required to determine the mass of fats removed in pounds.

We need to know that;

Density = Mass ÷ volume

1 L = 1000 mL, thus, volume is 3000 mL

Rearranging the formula;

Mass = Density × Volume

         = 0.94 g/mL × 3000 mL

         = 2,820 g

but, 1 pound = 453.592 g

Therefore;

Mass = 2,820 g ÷ 453.592 g per pound

         = 6.217 pounds

Thus, the amount of fats removed is 6.217 pounds

4 0
3 years ago
A volatile liquid is one that ______?
nasty-shy [4]

readily evaparates.


hope it helped :D

7 0
3 years ago
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