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PilotLPTM [1.2K]
2 years ago
5

Explain in words or using your diagrams how beryllium atoms would react with fluorine atoms.

Chemistry
1 answer:
Marysya12 [62]2 years ago
8 0

Explanation:

To delineate the the nature of the bonds that would be formed between the two elements, let us first write the electronic configuration of the two species;

  Be  = 2, 2

  F  = 2, 7

 Beryllium is a metal with two valence electrons whereas fluorine is a halogen with seven valence electrons.

When Be loses two electrons it becomes isoelectronic with He;

                 Be →  Be²⁺ + 2e⁻  

Also, when fluorine gains  an electron, it becomes isoelectronic with Ne;

               F  + e⁻ →  F⁻

This loss and gain of electrons between the two elements creates an electrostatic attraction them and they enter into an electrovalent bond.

      Hence;

           Be²⁺  + 2F⁻ → BeF₂

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On the other hand, at the beginning of the reaction there are no products. As the reaction happens, the products are being formed and their speed will increase to match the speed of the reagents. When the rates of products and reagents are equal and constant, it is possible to say that the reaction is in chemical equilibrium. At this point, both reactions continue to happen, but the total concentrations of reagents and products no longer change.

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