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Troyanec [42]
3 years ago
10

Radioactive decay can be described by the following equation where is the original amount of the substance, is the amount of the

substance remaining after time , and is a constant that is characteristic of the substance. For the radioactive isotope phosphorus-32, is . If the original amount of phosphorus-32 in a sample is 57.9 mg, how much phosphorus-32 remains after 13.7 days have passed
Chemistry
1 answer:
Murljashka [212]3 years ago
3 0

Answer:

29.8 mg

Explanation:

Just slightly less than 1/2 decay

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The isotope of an atom containing 31 protons and 39 neutrons suddenly has two neutrons added to it.
xxTIMURxx [149]

Answer:

Gallium-72

Explanation:

The elements are identified by the number of protons of the atom, which is its atomic number.

In this case the number of protons 39 (atomic number 39) permit you to identify the element as gallium.

Now, to identify the isotope you tell the name of the element and add the mass number.

The mass number is the sum of the protons and the neutrons

In this case, the number of neutrons is the original 39 plus the 2 added suddenly, i.e. 39 + 2 = 41, so the mass number is 31 + 41 = 72

Therefore, the isotope is gallium - 72.

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Which one is the catalyst?
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Answer:

the catalyst is the two gray dots

5 0
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Which choice can be classified as a pure substance?
ozzi

Answer:

d. compound

Explanation:

compound and elements are pure substances

8 0
3 years ago
A + B -&gt;C<br><br><br>Which situation best describes the effect of a limiting reactant?
anygoal [31]

Answer:

The Limiting Reactant is the reactant that when consumed the reaction stops.

Explanation:

7 0
3 years ago
___au2s3 ___h2 → ___au ___h2s
liberstina [14]
The best way to balance an equation is to balance one atom at a time.
You start with two Au atoms on the left, so you know the coefficient of Au on the right has to be 2. So at first we get,
Au2S3 + H2 --> 2Au + H2S
Then, notice you have 3 sulfur atoms on the left, so you need three on the right.
Our equation becomes
Au2S3 + H2 --> 2Au + 3H2S
Lastly, we now have six hydrogen atoms on the right, and only two on the left, so we assign a three to the H2 on the left
Au2S3 + 3H2 --> 2Au + 3H2S Is the balanced final equation.

7 0
3 years ago
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