The best and most correct answer among the choices provided by the question is the second choice , b. sodium hydroxide .
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Answer: 2 (2 neutrons are produced).
Explanation:
1) In the left side of the transmutation equationa appears:
²³⁵U + ¹n →
I am omitting the atomic number (subscript to the leff) because the question does not show them as it is focused on number of neutrons.
2) The right side of the transmutation equation has:
→ ¹⁴⁴Ce + ⁹⁰Sr + ?
3) The total mass number of the left side is 235 + 1 = 236
4) The total mass number of Ce and Sr on the right side is 144 + 90 = 234
5) Then, you are lacking 236 - 234 = 2 unit masses on the right side which are the 2 neutrons that are produced along with the Ce and Sr.
The complete final equation is:
²³⁵U + ¹n → ¹⁴⁴Ce + ⁹⁰Sr + 2 ¹n
Where you have the two neutrons produced.
Answer: dilute
Explanation:
A concentrated solution which is used to prepare solutions of lower concentrations by diluting it with addition of water.
A dilute solution is one which contains lower concentration.
Using Molarity equation:
=concentration of stock solution = 0.150 mol/L
= volume of stock solution = 10.0 ml
= concentration of dilute solution = ?
= volume of dilute solution = (10.0+90.0) ml = 100.0 ml


As the concentration is less than the original concentration, the solution is termed as dilute.
To times 4 and 3 together for mass and acceleration then your answer would be 12, So Force= 12
Refer to the diagram shown below.
The second axis is at the centroid of the rod.
The length of the rod is L = 100 cm = 1 m
The first axis is located at 20 cm = 0.2 m from the centroid.
Let m = the mass of the rod.
The moment of inertia about the centroid (the 2nd axis) is

According to the parallel axis theorem, the moment of inertia about the first axis is

The ratio of the moment of inertia through the 2nd axis (centroid) to that through the 1st axis is

Answer: 0.676