A sample of dry gas weighing 2.1025 g is found to occupy 2.850 L at 22.0oC and 740.0 mm Hg. How many moles of gas are present?
1 answer:
0.11 moles of the gas are present in the sample of dry gas.
Explanation:
Data given:
mass of the gas = 2.1025 grams
volume of the gas = 2.850 litres
temperature = 22 degrees (273.15+22) = 295.15 K
Pressure = 740 mm Hg or 0.973 atm
moles of the gas =?
R = 0.08206 atmL/Mole K
From the ideal gas law the number of moles can be calculated in the sample of dry gas. Number of moles will be determined by the pressure exerted, volume and temperature of the gas.
The formula:
PV = nRT
n =
putting the values in the above equation:
n =
= 0.11 moles
0.11 moles of the dry gas is present in the sample given.
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Explanation:
We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.
Next we will calculate how many moles of are present in 85.00 mL of 1.500 M sulfuric acid.
As, Molarity =
1.500 M =
n = 0.1275 mol
Now set up and solve a stoichiometric conversion from moles of to grams of
. As, the molar mass of
is 84.01 g/mol.
= 21.42 g
So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.