N₂ + 3 H₂ → 2 NH₃
number of moles of N₂ = 38 g / 28 g/mol = 1.357 mol
1 mole of N₂ gives 2 moles of NH₃
1.357 mol of N₂ will give ?? mole NH₃
= 2 x 1.357 = 2.7 mol NH₃
Answer: There are 20 milliliters of 1.0 M HCl is required to be diluted to make 200 mL of a 0.1 M solution.
Explanation:
Given:
= 1.0 M,
= ?
= 0.1 M,
= 200 mL
Formula used is as follows.

Substitute values into the above formula as follows.

Thus, we can conclude that there are 20 milliliters of 1.0 M HCl is required to be diluted to make 200 mL of a 0.1 M solution.
2nd
Explanation:
because i guesses i guess so yeah trust your gut buddy