Answer:
81 F
Step-by-step explanation:
Hours | Temp.
0 | 75F
1 | 77F
2 | 79F
3 | 81F
Answer:
Danny will watch all of them on the same day again on August 31
Step-by-step explanation:
Here, we have a word problem.
The shows and frequency of watching are;
Show A Every 2 days
Show B Every 3rd day
Show C Every 5th day
Show D Every 10th day
Danny watched all four shows on August 1, therefore, the day he will watch all four shows can be found by finding the Lowest Common Multiple, LCM of the frequency of his watching each of the shows. That is, the LCM of 2, 3, 5 and 10
Therefore we have, since 10 is the highest frequency and 3 is not a factor of 10, then the LCM that applies to 3 and 10 is 3×10 = 30.
Since the other frequencies are also a factor of 30, then the LCM of 2, 3, 5, and 10 is 30
Therefore, Danny will watch all four shows again on the same day again in 30 days after August 1. That is August (1 + 30) = August 31.
<u>Answer:</u>
A. y = -2 - cos(x-π)
<u>Explanation:</u>
<u>The general form of the trig equation is:</u>
y = A sin (Bx + C) + D
where:
A is the amplitude
is the period
is the phase shift
D is the vertical shift
<u>Now, let's check the choices:</u>
<u>A. y = -2 - cos(x-π)</u>

Therefore, the function has a phase shift of π
<u>B. y = 3 cos(4x)</u>

Therefore, the function has no phase shift
<u>C. y = tan(2x)</u>

Therefore, the function has no phase shift
<u>D. y = 1 + sin(x)</u>

Therefore, the function has no phase shift
<u>Based on the above,</u> the correct answer is A
Hope this helps :)
Area of the quarter sector
Area of the entire circle = pi * r^2
Area of the quarter circle = pi r^2 / 4
r = 9
Area of the quarter circle = pi 9^2 / 4
Area of the quarter circle = pi 81/4 = 20.25 pi
Area of the triangle
Area pf the triangle = 1/2 b*h
b = h = r
r = 9
Area of the triangle = 1/2 9 * 9
Area of teh triangle = 1/2 81
Area of the triangle = 40.5
Area of the shaded area
The shaded area = Area of the 1/4 circle - area of the triangle
The shaded area = (20.24 pi - 40.5)ft^2
A <<<<<< Answer.