Explanation:
Bonjour , pourriez-vous m'aider à faire cet exercice svp ??
a) Convertir les longueurs suivantes en utilisant les puissances de 10.
1,7 cm en mètre
0,48 km en mètre
49 mm en mètre
35 m en centimètre
63 km en mètre
568 Mm en kilomètre
b) Ecrire les longueurs ainsi converties en utilisant la notation scientifique
Not sure what you mean by "breaks in the tension" but I suspect you mean the rope will come apart if the tension in the rope exceeds 1800 N.
In the free body diagram for the 500 N weight, we have a figure Y with the net force equations
• horizontal net force:
∑ F[hor] = T₁ cos(θ) - T₂ cos(θ) = 0
• vertical net force:
∑ F[ver] = T₁ sin(θ) + T₂ sin(θ) - 500 N = 0
From the first equation, it follows that T₁ = T₂, so I'll denote their magnitude by T alone. From the second equation, we have
2 T sin(θ) = 500 N
and if the maximum permissible tension is T = 1800 N, it follows that
sin(θ) = (500 N) / (3600 N) ⇒ θ = arcsin(5/36) ≈ 7.9°
is the smallest angle the rope can make with the horizontal.
Answer:
Explanation:
The formula for centripetal acceleration is
and filling in:
and solving for r:
gives us that
r = 79.6 m
