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LekaFEV [45]
3 years ago
11

If it requires 7.0 JJ of work to stretch a particular spring by 1.7 cmcm from its equilibrium length, how much more work will be

required to stretch it an additional 3.6 cm ?
Physics
1 answer:
Lynna [10]3 years ago
3 0

Answer:

Explanation:

First of all, well calculate the spring constant k

K = 2Ei/x^2

Where Ei = initial work required

x = initial stretch length

k = 2×7/0.017^2 = 48443J/m^2

Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m

EF = kx^2/2

48443 × 0.053^2/2 = 68J

Work done in stretching additional 3.6cm is equal to

68J-7J = 61J

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Newtons second law in words??​
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Answer:

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Which of the following is not true about the Law of Conservation of Energy?
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The following is not true about the Law of Conservation of Energy:

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Pls help
belka [17]

Answer:

2156 J

Explanation:

From the question,

Work done = Combined mass of the bucket and water×height×gravity.

W = (M+m)hg............................. Equation 1

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Given: M = 20 kg, m = 2 kg, h = 10 m

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The answers would be:

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For direct relationships, you just need to remember, when one goes up, the other one goes up too.

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