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Alekssandra [29.7K]
4 years ago
6

How do rocks within Earth change as P waves pass? How do rocks within Earth change as P waves pass? Rocks within Earth both expa

nd and contract as P waves pass. Rocks within Earth neither expand nor contract as P waves pass. Rocks within Earth expand as P waves pass. Rocks within Earth contract as P waves pass.
Physics
1 answer:
ohaa [14]4 years ago
6 0

Rocks within Earth both expand and contract as P waves pass

Explanation:

Rocks within the earth both expands and contracts as P-waves passes through them. P-waves are elastic waves.

  • Elastic waves behaves in such a way that they do not cause permanent deformation of rocks.
  • They can be said to cause elastic deformation when they travel through rocks.
  • They simply temporarily expand and contract the rock within a short period by causing the vibration of particles of the medium.
  • After a short while, the rock returns back to its original position as if nothing has happened to it.
  • These elastic waves are better called seismic waves.
  • P-waves are primary waves that can travel through any medium.

Learn more:

Earthquakes brainly.com/question/11292835

#learnwithBrainly

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State the difference between sensible heat and latent heat
Anna11 [10]

<u>Latent hea</u>t is related to changes in phase between liquids ,gases and solids.

<u>Sensible heat</u> is related to changes in temperature of a gas or object with no change in phase.

6 0
3 years ago
Calculate the force of gravity between a comet with a mass of 500kg and a small asteroid with a mass of 20kg that is separated b
givi [52]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent gravitational force is ~

  • F  \approx1.48\times 10 {}^{ - 7}  \: \: N

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

We know that ~

\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}

where,

  • F = gravitational force

  • m_1 = mass of 1st object = 500 kg

  • m_2 = mass of 2nd object = 20kg

  • G = gravitational constant = 6.674 × {10}^ {-11}

  • r = distance between the objects = 2.12 m

Let's calculate the force ~

  • F = \dfrac{6.674   \times 10 {}^{ - 11} \times 500 \times 20}{(2.12) {}^{2} }

  • F = \dfrac{6.674  \times 10 {}^{ - 11} \times 10 {}^{4} }{4.4944}

  • F =  \dfrac{6.674}{4.4944}  \times 10 {}^{ - 7}

  • F =1.484 \times 10 {}^{ - 7}  \: \: newtons
7 0
2 years ago
Two bodies are falling with negligible air resistance, side by side, above a horizontal plane. If one of the bodies is given an
tankabanditka [31]

Answer:4-strikes the plane at same time as the other body

Explanation:

Given

If both bodies is falling on a horizontal plane and second body is given an acceleration in horizontal direction then it does not change the time to reach the Horizontal Plate as there is no change in vertical direction.

Horizontal acceleration will give only horizontal range and horizontal velocity.

8 0
3 years ago
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You can tell a lot about an object that's not moving,
and also a lot about the forces acting on it:

==> If the box is at rest on the table, then it is not accelerating.

==> Since it is not accelerating, I can say that the forces on it are balanced.

==> That means that the sum of all forces acting on the box is zero,
and the effect of all the forces acting on it is the same as if there were
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==> This in turn means that all of the horizontal forces are balanced,
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Horizontal forces:
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All of the forces on this list must add up to zero. So ...

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If nobody pushing the box, then sliding friction force = zero.

Vertical forces:
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All of the forces on this list must add up to zero, so ...

(Gravitational force down) + (normal force up) = zero

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6 0
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Answer: <span>C. 5.8 ft squared</span>
7 0
3 years ago
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