Calories would denote the amount of heat.
Givens are:
Mass = 500 g
t0 = 20C
tf = 30C
C = 1 cal/gC
Formula:
Q=MCt
500g (1cal/gC) 10C= 5000 cal
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The first one, directly proportional to the length that the spring is stretched.
Answer:
28.2 m/s
Explanation:
The range of a projectile launched from the ground is given by:

where
v is the initial speed
g = 9.8 m/s^2 is the acceleration of gravity
is the angle at which the projectile is thrown
In this problem we have
d = 81.1 m is the range
is the angle
Solving for v, we find the speed of the projectile:
