Answer:
0.446 mm
0.066 V/m
Explanation:
Given
We are given the length of the copper cable L = 3.30 km and the potential difference is V = 220 V
Solution
(a) We want to find the diameter d of the cable when the dissipated power is P = 50W. The power consumed by the cable depends on its resistance R and it is given by equation in the form
P= V^2/R (1)
Where V is the voltage in the cable. Now let us solve equation (1) for R and plug our values for V and P into equation (1) to get R
R = V^2/P = (220)^2/(50) = 968Ω
Now we can determine the diameter of the copper wire. The resistance R of the wires depends on the area of the wire, resistivity and the length of the cable. Where equation gives us the relationship between these variables in the form
R = pL/π*r^2 (solve for r)
r = √pL/πR (2)
Now we can plug our values for Rep and L into equation (2) to get the radius of the cable where p for copper equals 1.72 x 10-8 Ω m
r =√pL/πR
= √1.72 x 10-8 *3300m/968
= 0.234 mm
Therefore, the diameter is d= 2r = 2(0.234 mm) = 0.446 mm
(b) To determine the electric field we can use the values for the potential difference across the cable and the length of the cable, where the electric field is inversely proportional to the length of the cable as next
E =V/L
=220/3300m
= 0.066 V/m
Explanation:
The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically, it is given by :
...............(1)
Where m₁ and m₂ are masses
r is the distance between them
It is clear from equation (1) that :
1. The gravitational force between two objects is inversely proportional to the square of the distance between the two objects.
2. The gravitational force between two objects is proportional to the product of the masses of the two objects.
Hence, this is the required solution.
Answer:
The speed of the car after the break was applied is 90.46 m/s
Explanation:
Given;
initial velocity of the car, u = 26.8 m/s
accelertation of the car, a = -8.2 m/s²
time of motion, t = 14.3 s
final velocity, v = ?
Apply the following kinematic equation;
v = u + at
v = 26.8 + (-8.2 x 14.3)
v = 26.8 - 117.26
v = -90.46 m/s
magnitude of the final velocity = 90.46 m/s
Therefore, the speed of the car after the break was applied is 90.46 m/s
Gravity pulls to the centre of the earth. A ship floats in water because the water pushing it up (upthrust) is equal to the force<span> of gravity (weight) pulling it </span>down<span>. Friction also occurs when objects move through air. This is </span>called<span>air resistance.</span>
