Answer:
Their function is to produce sound by allowing the free edges of the folds to vibrate against one another and also to act as the laryngeal sphincter when they are closed.
Answer:
The acceleration of the ball is 4.18 [m/s^2]
Explanation:
By Newton's second law we can find the acceleration of the ball
![F = m*a\\where:\\F = force applied [N] or [kg*m/s^2]\\m = mass of the ball [kg]\\a = acceleration [m/s^s]](https://tex.z-dn.net/?f=F%20%3D%20m%2Aa%5C%5Cwhere%3A%5C%5CF%20%3D%20force%20applied%20%5BN%5D%20or%20%5Bkg%2Am%2Fs%5E2%5D%5C%5Cm%20%3D%20mass%20of%20the%20ball%20%5Bkg%5D%5C%5Ca%20%3D%20acceleration%20%5Bm%2Fs%5Es%5D)
Now we have:
![a = F/m\\a = \frac{1.8 [kg*m/s^s]}{0.43[kg]} \\a = 4.18 [kg]](https://tex.z-dn.net/?f=a%20%3D%20F%2Fm%5C%5Ca%20%3D%20%5Cfrac%7B1.8%20%5Bkg%2Am%2Fs%5Es%5D%7D%7B0.43%5Bkg%5D%7D%20%5C%5Ca%20%3D%204.18%20%5Bkg%5D)
Answer:
All of the arrows pointing up that have a red box NOT the arrow pointing down with a red box. (if the blue squigglies on the water are arrows then they count too, the picture is not too clear)
Explanation:
C. located in front of the lens
<span>Applied Force Direction vector = [0,1,3]
force F = j + 4k
torque is t = 100 Newton-meters = r x F
Wrench is 0.5 meters long on positive side of the y-axis, r = 0.6 = [0,0.6,0]
We know torque |t| = |r x F| = |r| x |F| sin theta
r x F = |r| x |F| cos theta
r x (j + 3k) = |r| x |j + 3k| cos theta
=> [0,0.6,0] [0,1,3] = 0.6 x squareroot of ((0)^2 + (1)^2 + (3)^2) cos theta
=> 0.6 = 0.6 x squareroot of (1 + 9) cos theta
=> cos theta = 1 / squareroot of (10)
Calculationg the sin theta,
sin theta = squareroot of (1 - (1 / squareroot of (10))^2) = squareroot of (9/10)
sin theta = 3 / squareroot of (10)
Substituting the values,
|T| = |r| x |F| sin theta => 100 = |0.6| x |F| x 3 / squareroot of (10)
|F| = (100 x squareroot of (10)) / 1.8
|F| = (1000 / 18) x squareroot of (10)
Magnitude of force |F| = 55.55 x squareroot of (10)</span>
