Answer:
see explanation
Step-by-step explanation:
Calculate C by adding corresponding components of A + B
C = ![\left[\begin{array}{ccc}4\\-7.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C-7.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-2.5\\5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2.5%5C%5C5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4-2.5\\-7.5+5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-2.5%5C%5C-7.5%2B5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}1.5\\-2.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1.5%5C%5C-2.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
One pear weighs 6 oz, you have 11 pears you multiply 11 by 6 getting 66 oz divided by 16 equals 4.25 lbs. Because there are 16 oz in 1 pound.
answer: No
Answer:
Yes, look at the explanation:
Step-by-step explanation:
- Calculate how many miles a car can drive with 1 gallon: 285 miles ÷ 10 = 28.5 miles with one gallon
- Divide 500 by 28.5 to calculate how many gallons are needed: 500 ÷ 28.5 ≈ 17.543 - Therefore yes, it is possible because the car uses about 17.543 gallons of gasoline for 500 miles.
Answer:
A=2πrh+2πr^2
Step-by-step explanation:
You have to convert the 30 inches into you know what and add them all together
