Urgent help needed Solve for x. Show your work.
1 answer:
Answer:
First exercise:
Second exercise:
Step-by-step explanation:
According to the Intersecting Secants Theorem the products of the segments of two secants that intersect each other outside a circle, are equal.
Knowing this, in order to solve the first exercise and the second exercise, we can write the following expressions and solve for "x":
For the first exercise, we get:
For the second exercise, we get:
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When you first look at thius graph, you should notice two things immedietly.
1. This graph will have a positive slope, because the line is going up.
2. the y-intercept is -2 because that's where it is on the y-axis.
Now, you have been given two points, (2, 1) and (0, -2). You can put these two points into the slope formula, which is: m =
= 
= 3/2.
So, now you have your slope and your y-intercept. Now, just put them into y = mx + b form!
y = 3/2x - 2 (it is ubtracting two instead of adding two because it is a negative two.)
Hope this helps!!
~Kiwi
1. This graph will have a positive slope, because the line is going up.
2. the y-intercept is -2 because that's where it is on the y-axis.
Now, you have been given two points, (2, 1) and (0, -2). You can put these two points into the slope formula, which is: m =
So, now you have your slope and your y-intercept. Now, just put them into y = mx + b form!
y = 3/2x - 2 (it is ubtracting two instead of adding two because it is a negative two.)
Hope this helps!!
~Kiwi