Question

Urgent help needed Solve for x. Show your work.

Answer 1

Answer:

First exercise: $x=7$

Second exercise: $x=2$

Step-by-step explanation:

According to the Intersecting Secants Theorem the products of the segments of two secants that intersect each other outside a circle, are equal.

Knowing this, in order to solve the first exercise and the second exercise, we can write  the following expressions and solve for "x":

For the first exercise, we get:

$(5)(5+x)=6(6+4)\\\\25+5x=60\\\\5x=60-25\\\\x=\frac{35}{5}\\\\x=7$

For the second exercise, we get:

$(4)(4+x)=3(3+5)\\\\16+4x=24\\\\4x=24-16\\\\x=\frac{8}{4}\\\\x=2$