Answer:
The answers are:
a) drinking 20–24 ounces of water for every pound of body mass lost,
b) stretching muscle groups, holding each stretch for 30 seconds or more, and
c) replenishing low blood sugar with carbohydrates
Explanation:
I just took the exam and got this correct.
Average velocity = Total Displacement / Total time taken
Total displacement is the distance from starting to end point.
35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle.
So displacement =
= 96.56 km
So, Total displacement = 96.56 km
So, Average Velocity = 96.56 / 2 = 48.28 km/hr
Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm.?
Point a is at the center of the square, and point b is at the empty corner closest to q2. Take the electric potential to be zero at a distance far from both charges.
(a) What is the electric potential at point a due to q1 and q2?
(b) What is the electric potential at point b?
(c) A point charge q3 = -6.00 μC moves from point a to point b. How much work is done on q3 by the electric forces exerted by q1 and q2?
Answer:
a) the potential is zero at the center .
Explanation:
a) since the two equal-magnitude and oppositely charged particles are equidistant
b)(b) Electric potential at point b, v = Σ kQ/r
r = 5cm = 0.05m
k = 8.99*10^9 N·m²/C²
Q = -2 microcoulomb
v= (8.99*10^9) * (2*10^-6) * (1/√2m - 1) / 0.0500m
v = -105 324 V
c)workdone = charge * potential
work = -6.00µC * -105324V
work = 0.632 J
From gas equations
PV/T = Constant
Then
P1V1/T1 = P2V2/T2, but V1 = V2
Therefore,
P1/T1 = P2/T2
P2 = (P1T2)/T1
P1 = 40 psi
T1 = 60°F = 288.706 K
T2 = 90°F = 305.372 K
Substituting;
P2 = (40*305.372)/288.706 = 42.31 psi
Then, gauge pressure would read 42.31 psi.
Well plants breathe carbon and let out oxygen so it cleans the air, not sure about the energy use...
